"золата" meaning in All languages combined

See золата on Wiktionary

Noun [白俄罗斯语]

Audio: Be-золата.ogg Forms: zólata [romanization], зо́лата, залаты́ [uncountable]
Etymology: 源自原始斯拉夫語 *zolto。與俄語 зо́лото (zóloto)同源。
  1. Sense id: zh-золата-be-noun-PB4xoZPN
The following are not (yet) sense-disambiguated
Derived forms: залаты́ (zalatý)

Download JSONL data for золата meaning in All languages combined (1.5kB)

{
  "categories": [
    {
      "kind": "other",
      "name": "派生自原始斯拉夫語的白俄羅斯語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始斯拉夫語的白俄羅斯語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語中性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語無生名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "roman": "zalatý",
      "word": "залаты́"
    }
  ],
  "etymology_text": "源自原始斯拉夫語 *zolto。與俄語 зо́лото (zóloto)同源。",
  "forms": [
    {
      "form": "zólata",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "зо́лата",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "залаты́",
      "raw_tags": [
        "相關形容詞"
      ],
      "tags": [
        "uncountable"
      ]
    }
  ],
  "lang": "白俄罗斯语",
  "lang_code": "be",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "金"
      ],
      "id": "zh-золата-be-noun-PB4xoZPN"
    }
  ],
  "sounds": [
    {
      "audio": "Be-золата.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/6e/Be-золата.ogg/Be-золата.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Be-золата.ogg",
      "raw_tags": [
        "音频"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "neuter"
  ],
  "word": "золата"
}
{
  "categories": [
    "派生自原始斯拉夫語的白俄羅斯語詞",
    "源自原始斯拉夫語的白俄羅斯語繼承詞",
    "白俄羅斯語不可數名詞",
    "白俄羅斯語中性名詞",
    "白俄羅斯語名詞",
    "白俄羅斯語無生名詞",
    "白俄羅斯語詞元"
  ],
  "derived": [
    {
      "roman": "zalatý",
      "word": "залаты́"
    }
  ],
  "etymology_text": "源自原始斯拉夫語 *zolto。與俄語 зо́лото (zóloto)同源。",
  "forms": [
    {
      "form": "zólata",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "зо́лата",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "залаты́",
      "raw_tags": [
        "相關形容詞"
      ],
      "tags": [
        "uncountable"
      ]
    }
  ],
  "lang": "白俄罗斯语",
  "lang_code": "be",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "金"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "Be-золата.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/6e/Be-золата.ogg/Be-золата.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Be-золата.ogg",
      "raw_tags": [
        "音频"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "neuter"
  ],
  "word": "золата"
}

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-07-01 from the zhwiktionary dump dated 2024-06-20 using wiktextract (e79c026 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.