"гвардия" meaning in All languages combined

See гвардия on Wiktionary

Noun [俄語]

Audio: Ru-гвардия.ogg Forms: gvárdija [romanization], гва́рдии, гва́рдии [nominative plural], гва́рдий [genitive plural]
Etymology: 借自意大利語 guardia.
  1. 衛隊
    Sense id: zh-гвардия-ru-noun-rxbcvXnh
The following are not (yet) sense-disambiguated

Noun [保加利亞語]

Forms: gvárdija [romanization]
Etymology: 借自俄語 гва́рдия (gvárdija),來自意大利語 guardia。
  1. 衛隊
    Sense id: zh-гвардия-bg-noun-rxbcvXnh
  2. 在某領域最精銳和最有經驗的人
    Sense id: zh-гвардия-bg-noun-F4EV8Uu0
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "保加利亞語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "保加利亞語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自俄語的保加利亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自意大利語的保加利亞語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自俄語的保加利亞語借詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自意大利語的保加利亞語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自俄語 гва́рдия (gvárdija),來自意大利語 guardia。",
  "forms": [
    {
      "form": "gvárdija",
      "tags": [
        "romanization"
      ]
    }
  ],
  "lang": "保加利亞語",
  "lang_code": "bg",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "衛隊"
      ],
      "id": "zh-гвардия-bg-noun-rxbcvXnh"
    },
    {
      "glosses": [
        "在某領域最精銳和最有經驗的人"
      ],
      "id": "zh-гвардия-bg-noun-F4EV8Uu0"
    }
  ],
  "tags": [
    "feminine"
  ],
  "word": "гвардия"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "俄語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有2個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自意大利語的俄語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自意大利語的俄語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自意大利語 guardia.",
  "forms": [
    {
      "form": "gvárdija",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "гва́рдии",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "гва́рдии",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "гва́рдий",
      "tags": [
        "genitive plural"
      ]
    }
  ],
  "lang": "俄語",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "衛隊"
      ],
      "id": "zh-гвардия-ru-noun-rxbcvXnh"
    }
  ],
  "sounds": [
    {
      "audio": "Ru-гвардия.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/Ru-гвардия.ogg/Ru-гвардия.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Ru-гвардия.ogg",
      "raw_tags": [
        "Audio"
      ]
    }
  ],
  "tags": [
    "feminine",
    "inanimate"
  ],
  "word": "гвардия"
}
{
  "categories": [
    "俄語名詞",
    "俄語詞元",
    "有2個詞條的頁面",
    "派生自意大利語的俄語詞",
    "源自意大利語的俄語借詞"
  ],
  "etymology_text": "借自意大利語 guardia.",
  "forms": [
    {
      "form": "gvárdija",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "гва́рдии",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "гва́рдии",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "гва́рдий",
      "tags": [
        "genitive plural"
      ]
    }
  ],
  "lang": "俄語",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "衛隊"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "Ru-гвардия.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/3/3a/Ru-гвардия.ogg/Ru-гвардия.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Ru-гвардия.ogg",
      "raw_tags": [
        "Audio"
      ]
    }
  ],
  "tags": [
    "feminine",
    "inanimate"
  ],
  "word": "гвардия"
}

{
  "categories": [
    "保加利亞語名詞",
    "保加利亞語詞元",
    "有2個詞條的頁面",
    "派生自俄語的保加利亞語詞",
    "派生自意大利語的保加利亞語詞",
    "源自俄語的保加利亞語借詞",
    "源自意大利語的保加利亞語借詞"
  ],
  "etymology_text": "借自俄語 гва́рдия (gvárdija),來自意大利語 guardia。",
  "forms": [
    {
      "form": "gvárdija",
      "tags": [
        "romanization"
      ]
    }
  ],
  "lang": "保加利亞語",
  "lang_code": "bg",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "衛隊"
      ]
    },
    {
      "glosses": [
        "在某領域最精銳和最有經驗的人"
      ]
    }
  ],
  "tags": [
    "feminine"
  ],
  "word": "гвардия"
}

Download raw JSONL data for гвардия meaning in All languages combined (1.5kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-05 from the zhwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.