See dood in All languages combined, or Wiktionary
Download JSONL data for dood meaning in 荷蘭語 (4.9kB)
{
"categories": [
{
"kind": "other",
"name": "派生自中古荷蘭語的荷蘭語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自原始日耳曼語的荷蘭語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古荷蘭語的荷蘭語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自中古荷蘭語的荷蘭語繼承詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自原始日耳曼語的荷蘭語繼承詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自古荷蘭語的荷蘭語繼承詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語形容詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語迴文",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōt ← 原始日耳曼語 *daudaz。對比西弗里斯蘭語 dead, 德語 tot, 英語 dead, 丹麥語 død。",
"forms": [
{
"form": "doder",
"tags": [
"comparative"
]
},
{
"form": "doodst",
"tags": [
"superlative"
]
}
],
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "adj",
"senses": [
{
"glosses": [
"死的"
],
"id": "zh-dood-nl-adj-4nBEf9lC"
}
],
"sounds": [
{
"ipa": "/doːt/"
},
{
"audio": "Nl-dood.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/15/Nl-dood.ogg/Nl-dood.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-dood.ogg",
"raw_tags": [
"音頻"
]
}
],
"word": "dood"
}
{
"derived": [
{
"word": "dode"
},
{
"word": "doden"
},
{
"word": "dooddoener"
},
{
"word": "een broertje dood hebben"
},
{
"word": "hersendood"
},
{
"roman": "secondary motivation",
"word": "monddood"
}
],
"descendants": [
{
"lang_code": "af",
"word": "dood"
}
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōt ← 原始日耳曼語 *daudaz。對比西弗里斯蘭語 dead, 德語 tot, 英語 dead, 丹麥語 død。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "adj",
"senses": [
{
"id": "zh-dood-nl-adj-47DEQpj8",
"tags": [
"no-gloss"
]
}
],
"word": "dood"
}
{
"categories": [
{
"kind": "other",
"name": "派生自中古荷蘭語的荷蘭語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自原始日耳曼語的荷蘭語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古荷蘭語的荷蘭語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自中古荷蘭語的荷蘭語繼承詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自原始日耳曼語的荷蘭語繼承詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自古荷蘭語的荷蘭語繼承詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語副詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語迴文",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōt ← 原始日耳曼語 *daudaz。對比西弗里斯蘭語 dead, 德語 tot, 英語 dead, 丹麥語 død。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "adv",
"senses": [
{
"glosses": [
"(弗萊芒) 很"
],
"id": "zh-dood-nl-adv-dLNRpfaQ",
"tags": [
"colloquial"
]
}
],
"word": "dood"
}
{
"categories": [
{
"kind": "other",
"name": "荷蘭語不可數名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語迴文",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語陽性名詞",
"parents": [],
"source": "w"
}
],
"derived": [
{
"word": "de dood of de gladiolen"
},
{
"word": "doodsbleek"
},
{
"roman": "“死因”",
"word": "doodsoorzaak f"
},
{
"word": "doodstraf"
},
{
"word": "doodvonnis"
},
{
"word": "doodziek"
},
{
"word": "hersendood"
}
],
"descendants": [
{
"lang_code": "af",
"word": "dood"
}
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōth, dōt ← 原始日耳曼語 *dauþuz。對比西弗里斯蘭語 dead, 德語 Tod, 英語 death, 丹麥語 død。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "noun",
"senses": [
{
"glosses": [
"死亡"
],
"id": "zh-dood-nl-noun-gtMTD6WC"
}
],
"tags": [
"masculine",
"uncountable"
],
"word": "dood"
}
{
"categories": [
{
"kind": "other",
"name": "荷蘭語動詞變位形式",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語迴文",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "荷蘭語非詞元形式",
"parents": [],
"source": "w"
}
],
"etymology_text": "源自doden。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "verb",
"senses": [
{
"form_of": [
{
"word": "doden"
}
],
"glosses": [
"doden的第一人稱單數現在時直陳式。"
],
"id": "zh-dood-nl-verb-LT4IQGw2",
"tags": [
"form-of"
]
},
{
"form_of": [
{
"word": "doden"
}
],
"glosses": [
"doden的命令式。"
],
"id": "zh-dood-nl-verb-LMZrooep",
"tags": [
"form-of"
]
}
],
"word": "dood"
}
{
"categories": [
"派生自中古荷蘭語的荷蘭語詞",
"派生自原始日耳曼語的荷蘭語詞",
"派生自古荷蘭語的荷蘭語詞",
"源自中古荷蘭語的荷蘭語繼承詞",
"源自原始日耳曼語的荷蘭語繼承詞",
"源自古荷蘭語的荷蘭語繼承詞",
"荷蘭語形容詞",
"荷蘭語詞元",
"荷蘭語迴文"
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōt ← 原始日耳曼語 *daudaz。對比西弗里斯蘭語 dead, 德語 tot, 英語 dead, 丹麥語 død。",
"forms": [
{
"form": "doder",
"tags": [
"comparative"
]
},
{
"form": "doodst",
"tags": [
"superlative"
]
}
],
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "adj",
"senses": [
{
"glosses": [
"死的"
]
}
],
"sounds": [
{
"ipa": "/doːt/"
},
{
"audio": "Nl-dood.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/15/Nl-dood.ogg/Nl-dood.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Nl-dood.ogg",
"raw_tags": [
"音頻"
]
}
],
"word": "dood"
}
{
"derived": [
{
"word": "dode"
},
{
"word": "doden"
},
{
"word": "dooddoener"
},
{
"word": "een broertje dood hebben"
},
{
"word": "hersendood"
},
{
"roman": "secondary motivation",
"word": "monddood"
}
],
"descendants": [
{
"lang_code": "af",
"word": "dood"
}
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōt ← 原始日耳曼語 *daudaz。對比西弗里斯蘭語 dead, 德語 tot, 英語 dead, 丹麥語 død。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "adj",
"senses": [
{
"tags": [
"no-gloss"
]
}
],
"word": "dood"
}
{
"categories": [
"派生自中古荷蘭語的荷蘭語詞",
"派生自原始日耳曼語的荷蘭語詞",
"派生自古荷蘭語的荷蘭語詞",
"源自中古荷蘭語的荷蘭語繼承詞",
"源自原始日耳曼語的荷蘭語繼承詞",
"源自古荷蘭語的荷蘭語繼承詞",
"荷蘭語副詞",
"荷蘭語詞元",
"荷蘭語迴文"
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōt ← 原始日耳曼語 *daudaz。對比西弗里斯蘭語 dead, 德語 tot, 英語 dead, 丹麥語 død。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "adv",
"senses": [
{
"glosses": [
"(弗萊芒) 很"
],
"tags": [
"colloquial"
]
}
],
"word": "dood"
}
{
"categories": [
"荷蘭語不可數名詞",
"荷蘭語名詞",
"荷蘭語詞元",
"荷蘭語迴文",
"荷蘭語陽性名詞"
],
"derived": [
{
"word": "de dood of de gladiolen"
},
{
"word": "doodsbleek"
},
{
"roman": "“死因”",
"word": "doodsoorzaak f"
},
{
"word": "doodstraf"
},
{
"word": "doodvonnis"
},
{
"word": "doodziek"
},
{
"word": "hersendood"
}
],
"descendants": [
{
"lang_code": "af",
"word": "dood"
}
],
"etymology_text": "源自中古荷蘭語 dôot, doet ← 古荷蘭語 dōth, dōt ← 原始日耳曼語 *dauþuz。對比西弗里斯蘭語 dead, 德語 Tod, 英語 death, 丹麥語 død。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "noun",
"senses": [
{
"glosses": [
"死亡"
]
}
],
"tags": [
"masculine",
"uncountable"
],
"word": "dood"
}
{
"categories": [
"荷蘭語動詞變位形式",
"荷蘭語迴文",
"荷蘭語非詞元形式"
],
"etymology_text": "源自doden。",
"lang": "荷蘭語",
"lang_code": "nl",
"pos": "verb",
"senses": [
{
"form_of": [
{
"word": "doden"
}
],
"glosses": [
"doden的第一人稱單數現在時直陳式。"
],
"tags": [
"form-of"
]
},
{
"form_of": [
{
"word": "doden"
}
],
"glosses": [
"doden的命令式。"
],
"tags": [
"form-of"
]
}
],
"word": "dood"
}
This page is a part of the kaikki.org machine-readable 荷蘭語 dictionary. This dictionary is based on structured data extracted on 2024-07-01 from the zhwiktionary dump dated 2024-06-20 using wiktextract (e79c026 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.