"diet" meaning in 荷兰语

{
  "categories": [
    {
      "kind": "other",
      "name": "有11個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自中古荷蘭語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始印歐語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始西日耳曼語的荷蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語中性名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "荷蘭語詞元",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "弗兰芒民族主义者对中古荷蘭語 diet (“人民”)的重新起用，源自原始西日耳曼語 *þeudu，源自原始日耳曼語 *þeudō，源自原始印歐語 *tewtéh₂。对比Diets (“荷兰的，德国的”)。",
  "lang": "荷兰语",
  "lang_code": "nl",
  "pos": "noun",
  "pos_title": "名词",
  "related": [
    {
      "word": "diedenweg"
    },
    {
      "word": "diets"
    },
    {
      "word": "diets maken"
    },
    {
      "word": "Diets"
    },
    {
      "word": "Dietsland"
    },
    {
      "word": "Platdiets"
    },
    {
      "word": "beduiden"
    },
    {
      "word": "duiden"
    },
    {
      "word": "duidelijk"
    },
    {
      "word": "verduidelijken"
    },
    {
      "word": "Duits"
    },
    {
      "word": "Duitsland"
    },
    {
      "word": "Nederduits"
    }
  ],
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "有古舊詞義的荷蘭語詞",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "人民"
      ],
      "id": "zh-diet-nl-noun-DP4bPBuy",
      "tags": [
        "archaic"
      ]
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "有古舊詞義的荷蘭語詞",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "比利时荷蘭語",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "弗兰芒人、荷兰人及阿非利堪人"
      ],
      "id": "zh-diet-nl-noun-3IypVko~",
      "raw_tags": [
        "比利时"
      ],
      "tags": [
        "archaic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/dit/"
    }
  ],
  "tags": [
    "neuter",
    "uncountable"
  ],
  "word": "diet"
}

{
  "categories": [
    "有11個詞條的頁面",
    "有詞條的頁面",
    "派生自中古荷蘭語的荷蘭語詞",
    "派生自原始印歐語的荷蘭語詞",
    "派生自原始日耳曼語的荷蘭語詞",
    "派生自原始西日耳曼語的荷蘭語詞",
    "荷蘭語不可數名詞",
    "荷蘭語中性名詞",
    "荷蘭語名詞",
    "荷蘭語詞元"
  ],
  "etymology_text": "弗兰芒民族主义者对中古荷蘭語 diet (“人民”)的重新起用，源自原始西日耳曼語 *þeudu，源自原始日耳曼語 *þeudō，源自原始印歐語 *tewtéh₂。对比Diets (“荷兰的，德国的”)。",
  "lang": "荷兰语",
  "lang_code": "nl",
  "pos": "noun",
  "pos_title": "名词",
  "related": [
    {
      "word": "diedenweg"
    },
    {
      "word": "diets"
    },
    {
      "word": "diets maken"
    },
    {
      "word": "Diets"
    },
    {
      "word": "Dietsland"
    },
    {
      "word": "Platdiets"
    },
    {
      "word": "beduiden"
    },
    {
      "word": "duiden"
    },
    {
      "word": "duidelijk"
    },
    {
      "word": "verduidelijken"
    },
    {
      "word": "Duits"
    },
    {
      "word": "Duitsland"
    },
    {
      "word": "Nederduits"
    }
  ],
  "senses": [
    {
      "categories": [
        "有古舊詞義的荷蘭語詞"
      ],
      "glosses": [
        "人民"
      ],
      "tags": [
        "archaic"
      ]
    },
    {
      "categories": [
        "有古舊詞義的荷蘭語詞",
        "比利时荷蘭語"
      ],
      "glosses": [
        "弗兰芒人、荷兰人及阿非利堪人"
      ],
      "raw_tags": [
        "比利时"
      ],
      "tags": [
        "archaic"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/dit/"
    }
  ],
  "tags": [
    "neuter",
    "uncountable"
  ],
  "word": "diet"
}