"брод" meaning in 白俄羅斯語

See брод in All languages combined, or Wiktionary

Noun

Forms: brod [romanization], бро́ду, брады́ [nominative plural], брадо́ў [genitive plural]
Etymology: 繼承自古白俄羅斯語 бродъ (brod),來自古東斯拉夫語 бродъ (brodŭ),來自原始斯拉夫語 *brodъ。
  1. 淺灘
    Sense id: zh-брод-be-noun-XqWjknIv
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "有5個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始斯拉夫語的白俄羅斯語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古東斯拉夫語的白俄羅斯語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古白俄羅斯語的白俄羅斯語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始斯拉夫語的白俄羅斯語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古東斯拉夫語的白俄羅斯語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古白俄羅斯語的白俄羅斯語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語無生名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "白俄羅斯語陽性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "繼承自古白俄羅斯語 бродъ (brod),來自古東斯拉夫語 бродъ (brodŭ),來自原始斯拉夫語 *brodъ。",
  "forms": [
    {
      "form": "brod",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "бро́ду",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "брады́",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "брадо́ў",
      "tags": [
        "genitive plural"
      ]
    }
  ],
  "lang": "白俄羅斯語",
  "lang_code": "be",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "淺灘"
      ],
      "id": "zh-брод-be-noun-XqWjknIv"
    }
  ],
  "tags": [
    "inanimate",
    "masculine"
  ],
  "word": "брод"
}
{
  "categories": [
    "有5個詞條的頁面",
    "有詞條的頁面",
    "派生自原始斯拉夫語的白俄羅斯語詞",
    "派生自古東斯拉夫語的白俄羅斯語詞",
    "派生自古白俄羅斯語的白俄羅斯語詞",
    "源自原始斯拉夫語的白俄羅斯語繼承詞",
    "源自古東斯拉夫語的白俄羅斯語繼承詞",
    "源自古白俄羅斯語的白俄羅斯語繼承詞",
    "白俄羅斯語名詞",
    "白俄羅斯語無生名詞",
    "白俄羅斯語詞元",
    "白俄羅斯語陽性名詞"
  ],
  "etymology_text": "繼承自古白俄羅斯語 бродъ (brod),來自古東斯拉夫語 бродъ (brodŭ),來自原始斯拉夫語 *brodъ。",
  "forms": [
    {
      "form": "brod",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "бро́ду",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "брады́",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "брадо́ў",
      "tags": [
        "genitive plural"
      ]
    }
  ],
  "lang": "白俄羅斯語",
  "lang_code": "be",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "淺灘"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "masculine"
  ],
  "word": "брод"
}

Download raw JSONL data for брод meaning in 白俄羅斯語 (1.0kB)


This page is a part of the kaikki.org machine-readable 白俄羅斯語 dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the zhwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.