патологія in 烏克蘭語

Audio: LL-Q8798 (ukr)-Tohaomg-патологія.wav

Forms: патоло́гія [canonical], patolóhija [romanization], патоло́гії [genitive], патоло́гії [nominative, plural], патоло́гій [genitive, plural], патологі́чний [relational, adjective] [Show additional information ▼] [Hide additional information ▲]

Etymology: 最终源自古希臘語 πάθος (páthos)，後綴-ло́гія (-lóhija)來自古希臘語 -λογία (-logía)。對照俄語 патоло́гия (patológija)、白俄羅斯語 патало́гія (patalóhija)、波蘭語 patologia。

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "含有後綴-логія的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語 病理學",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語無生名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語陰性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "最终源自古希臘語 πάθος (páthos)，後綴-ло́гія (-lóhija)來自古希臘語 -λογία (-logía)。對照俄語 патоло́гия (patológija)、白俄羅斯語 патало́гія (patalóhija)、波蘭語 patologia。",
  "forms": [
    {
      "form": "патоло́гія",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "patolóhija",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "патоло́гії",
      "tags": [
        "genitive"
      ]
    },
    {
      "form": "патоло́гії",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "патоло́гій",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "патологі́чний",
      "tags": [
        "relational",
        "adjective"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
  "related": [
    {
      "roman": "patóloh",
      "sense": "病理學家",
      "word": "пато́лог"
    }
  ],
  "senses": [
    {
      "glosses": [
        "病理學"
      ],
      "id": "zh-патологія-uk-noun-WkBtXjHQ"
    }
  ],
  "sounds": [
    {
      "audio": "LL-Q8798 (ukr)-Tohaomg-патологія.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/1b/LL-Q8798_(ukr)-Tohaomg-патологія.wav/LL-Q8798_(ukr)-Tohaomg-патологія.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/1b/LL-Q8798_(ukr)-Tohaomg-патологія.wav/LL-Q8798_(ukr)-Tohaomg-патологія.wav.ogg",
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q8798 (ukr)-Tohaomg-патологія.wav"
    }
  ],
  "tags": [
    "feminine",
    "inanimate"
  ],
  "word": "патологія"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "含有後綴-логія的烏克蘭語詞",
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自古希臘語的烏克蘭語詞",
    "烏克蘭語 病理學",
    "烏克蘭語名詞",
    "烏克蘭語無生名詞",
    "烏克蘭語詞元",
    "烏克蘭語陰性名詞"
  ],
  "etymology_text": "最终源自古希臘語 πάθος (páthos)，後綴-ло́гія (-lóhija)來自古希臘語 -λογία (-logía)。對照俄語 патоло́гия (patológija)、白俄羅斯語 патало́гія (patalóhija)、波蘭語 patologia。",
  "forms": [
    {
      "form": "патоло́гія",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "patolóhija",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "патоло́гії",
      "tags": [
        "genitive"
      ]
    },
    {
      "form": "патоло́гії",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "патоло́гій",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "патологі́чний",
      "tags": [
        "relational",
        "adjective"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
  "related": [
    {
      "roman": "patóloh",
      "sense": "病理學家",
      "word": "пато́лог"
    }
  ],
  "senses": [
    {
      "glosses": [
        "病理學"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "LL-Q8798 (ukr)-Tohaomg-патологія.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/1b/LL-Q8798_(ukr)-Tohaomg-патологія.wav/LL-Q8798_(ukr)-Tohaomg-патологія.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/1b/LL-Q8798_(ukr)-Tohaomg-патологія.wav/LL-Q8798_(ukr)-Tohaomg-патологія.wav.ogg",
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q8798 (ukr)-Tohaomg-патологія.wav"
    }
  ],
  "tags": [
    "feminine",
    "inanimate"
  ],
  "word": "патологія"
}

This page is a part of the kaikki.org machine-readable 烏克蘭語 dictionary. This dictionary is based on structured data extracted on 2025-07-31 from the zhwiktionary dump dated 2025-07-20 using wiktextract (ed078bd and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"патологія" meaning in 烏克蘭語

Noun