"люд" meaning in 烏克蘭語

See люд in All languages combined, or Wiktionary

Noun

Forms: ljud [romanization], лю́ду
Etymology: 來自原始斯拉夫語 *ľudъ。
  1. 人們,民眾 Tags: literary
    Sense id: zh-люд-uk-noun-l9670WZq
The following are not (yet) sense-disambiguated
Derived forms: людськи́й (ljudsʹkýj)

Download JSONL data for люд meaning in 烏克蘭語 (1.6kB)

{
  "categories": [
    {
      "kind": "other",
      "name": "有多餘標題行參數的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始印歐語的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始斯拉夫語的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始波羅的-斯拉夫語的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始斯拉夫語的烏克蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始波羅的-斯拉夫語的烏克蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語不可數名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語無生名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語陽性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "roman": "ljudsʹkýj",
      "word": "людськи́й"
    }
  ],
  "etymology_text": "來自原始斯拉夫語 *ľudъ。",
  "forms": [
    {
      "form": "ljud",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "лю́ду",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "notes": [
    "本詞為集合名詞,區分自лю́ди (ljúdy, “人”, 複數名詞)。"
  ],
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "人們,民眾"
      ],
      "id": "zh-люд-uk-noun-l9670WZq",
      "tags": [
        "literary"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "masculine",
    "uncountable"
  ],
  "word": "люд"
}
{
  "categories": [
    "有多餘標題行參數的烏克蘭語詞",
    "派生自原始印歐語的烏克蘭語詞",
    "派生自原始斯拉夫語的烏克蘭語詞",
    "派生自原始波羅的-斯拉夫語的烏克蘭語詞",
    "源自原始斯拉夫語的烏克蘭語繼承詞",
    "源自原始波羅的-斯拉夫語的烏克蘭語繼承詞",
    "烏克蘭語不可數名詞",
    "烏克蘭語名詞",
    "烏克蘭語無生名詞",
    "烏克蘭語詞元",
    "烏克蘭語陽性名詞"
  ],
  "derived": [
    {
      "roman": "ljudsʹkýj",
      "word": "людськи́й"
    }
  ],
  "etymology_text": "來自原始斯拉夫語 *ľudъ。",
  "forms": [
    {
      "form": "ljud",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "лю́ду",
      "raw_tags": [
        "屬格"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "notes": [
    "本詞為集合名詞,區分自лю́ди (ljúdy, “人”, 複數名詞)。"
  ],
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "人們,民眾"
      ],
      "tags": [
        "literary"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "masculine",
    "uncountable"
  ],
  "word": "люд"
}

This page is a part of the kaikki.org machine-readable 烏克蘭語 dictionary. This dictionary is based on structured data extracted on 2024-06-29 from the zhwiktionary dump dated 2024-06-20 using wiktextract (d4b8e84 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.