"вугор" meaning in 烏克蘭語

See вугор in All languages combined, or Wiktionary

Noun

Audio: Uk-вугор.ogg Forms: vuhór [romanization], вугра́, вугри́ [nominative plural], вугрі́в [genitive plural]
Etymology: 来自原始斯拉夫語 *ǫgořь。
  1. 鰻魚,鱔魚
    Sense id: zh-вугор-uk-noun-10DCYAdi
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自原始斯拉夫語的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自原始斯拉夫語的烏克蘭語繼承詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語無生名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語陽性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "来自原始斯拉夫語 *ǫgořь。",
  "forms": [
    {
      "form": "vuhór",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "вугра́",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "вугри́",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "вугрі́в",
      "tags": [
        "genitive plural"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "glosses": [
        "鰻魚,鱔魚"
      ],
      "id": "zh-вугор-uk-noun-10DCYAdi"
    }
  ],
  "sounds": [
    {
      "audio": "Uk-вугор.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/ee/Uk-вугор.ogg/Uk-вугор.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Uk-вугор.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "masculine"
  ],
  "word": "вугор"
}
{
  "categories": [
    "有1個詞條的頁面",
    "有詞條的頁面",
    "派生自原始斯拉夫語的烏克蘭語詞",
    "源自原始斯拉夫語的烏克蘭語繼承詞",
    "烏克蘭語名詞",
    "烏克蘭語無生名詞",
    "烏克蘭語詞元",
    "烏克蘭語陽性名詞"
  ],
  "etymology_text": "来自原始斯拉夫語 *ǫgořь。",
  "forms": [
    {
      "form": "vuhór",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "вугра́",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "вугри́",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "вугрі́в",
      "tags": [
        "genitive plural"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "glosses": [
        "鰻魚,鱔魚"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "Uk-вугор.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/e/ee/Uk-вугор.ogg/Uk-вугор.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Uk-вугор.ogg",
      "raw_tags": [
        "音頻"
      ]
    }
  ],
  "tags": [
    "inanimate",
    "masculine"
  ],
  "word": "вугор"
}

Download raw JSONL data for вугор meaning in 烏克蘭語 (1.0kB)


This page is a part of the kaikki.org machine-readable 烏克蘭語 dictionary. This dictionary is based on structured data extracted on 2025-01-31 from the zhwiktionary dump dated 2025-01-20 using wiktextract (bcd5c38 and 9dbd323). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.