"бродяга" meaning in 烏克蘭語

See бродяга in All languages combined, or Wiktionary

Noun

Audio: Uk-бродяга.ogg Forms: бродя́га [canonical], brodjáha [romanization], бродя́ги [genitive], бродя́ги [nominative, plural], бродя́г [genitive, plural]
Etymology: 來自бродити (brodyty) + -яга (-jaha)。
  1. 流浪漢,遊民
    Sense id: zh-бродяга-uk-noun-20ogGqET
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "含有後綴-яга的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有3個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語無生名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語陰性名詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "來自бродити (brodyty) + -яга (-jaha)。",
  "forms": [
    {
      "form": "бродя́га",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "brodjáha",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "бродя́ги",
      "tags": [
        "genitive"
      ]
    },
    {
      "form": "бродя́ги",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "бродя́г",
      "tags": [
        "genitive",
        "plural"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "glosses": [
        "流浪漢,遊民"
      ],
      "id": "zh-бродяга-uk-noun-20ogGqET"
    }
  ],
  "sounds": [
    {
      "audio": "Uk-бродяга.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/59/Uk-бродяга.ogg/Uk-бродяга.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Uk-бродяга.ogg"
    }
  ],
  "tags": [
    "feminine",
    "inanimate"
  ],
  "word": "бродяга"
}
{
  "categories": [
    "含有後綴-яга的烏克蘭語詞",
    "有3個詞條的頁面",
    "有詞條的頁面",
    "烏克蘭語名詞",
    "烏克蘭語無生名詞",
    "烏克蘭語詞元",
    "烏克蘭語陰性名詞"
  ],
  "etymology_text": "來自бродити (brodyty) + -яга (-jaha)。",
  "forms": [
    {
      "form": "бродя́га",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "brodjáha",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "бродя́ги",
      "tags": [
        "genitive"
      ]
    },
    {
      "form": "бродя́ги",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "бродя́г",
      "tags": [
        "genitive",
        "plural"
      ]
    }
  ],
  "lang": "烏克蘭語",
  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
  "senses": [
    {
      "glosses": [
        "流浪漢,遊民"
      ]
    }
  ],
  "sounds": [
    {
      "audio": "Uk-бродяга.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/5/59/Uk-бродяга.ogg/Uk-бродяга.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Uk-бродяга.ogg"
    }
  ],
  "tags": [
    "feminine",
    "inanimate"
  ],
  "word": "бродяга"
}

Download raw JSONL data for бродяга meaning in 烏克蘭語 (1.0kB)


This page is a part of the kaikki.org machine-readable 烏克蘭語 dictionary. This dictionary is based on structured data extracted on 2025-08-03 from the zhwiktionary dump dated 2025-08-01 using wiktextract (a681f8a and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.