"бандит" meaning in 烏克蘭語

See бандит in All languages combined, or Wiktionary

Noun

Audio: Uk-бандит.ogg Forms: bandýt [romanization], банди́та, банди́ти [nominative plural], банди́тів [genitive plural], банди́тка [feminine], банди́тський
Etymology: 借自意大利語 bandito。
  1. 盜賊
    Sense id: zh-бандит-uk-noun-je9f7HK5
The following are not (yet) sense-disambiguated
Synonyms (盜賊): га́нгстер (hánhster), розбі́йник (rozbíjnyk)
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      "kind": "other",
      "name": "有5個詞條的頁面",
      "parents": [],
      "source": "w"
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      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
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    {
      "kind": "other",
      "name": "派生自意大利語的烏克蘭語詞",
      "parents": [],
      "source": "w"
    },
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      "kind": "other",
      "name": "源自意大利語的烏克蘭語借詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語 犯罪",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "烏克蘭語 男性",
      "parents": [],
      "source": "w"
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      "parents": [],
      "source": "w"
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      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自意大利語 bandito。",
  "forms": [
    {
      "form": "bandýt",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "банди́та",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "банди́ти",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "банди́тів",
      "tags": [
        "genitive plural"
      ]
    },
    {
      "form": "банди́тка",
      "tags": [
        "feminine"
      ]
    },
    {
      "form": "банди́тський",
      "raw_tags": [
        "關係形容詞"
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    }
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  "lang": "烏克蘭語",
  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
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        "盜賊"
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  "synonyms": [
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      "roman": "hánhster",
      "sense": "盜賊",
      "word": "га́нгстер"
    },
    {
      "roman": "rozbíjnyk",
      "sense": "盜賊",
      "word": "розбі́йник"
    }
  ],
  "tags": [
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  ],
  "word": "бандит"
}
{
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    "有詞條的頁面",
    "派生自意大利語的烏克蘭語詞",
    "源自意大利語的烏克蘭語借詞",
    "烏克蘭語 犯罪",
    "烏克蘭語 男性",
    "烏克蘭語個人名詞",
    "烏克蘭語名詞",
    "烏克蘭語詞元",
    "烏克蘭語陽性名詞"
  ],
  "etymology_text": "借自意大利語 bandito。",
  "forms": [
    {
      "form": "bandýt",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "банди́та",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "банди́ти",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "банди́тів",
      "tags": [
        "genitive plural"
      ]
    },
    {
      "form": "банди́тка",
      "tags": [
        "feminine"
      ]
    },
    {
      "form": "банди́тський",
      "raw_tags": [
        "關係形容詞"
      ]
    }
  ],
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  "lang_code": "uk",
  "pos": "noun",
  "pos_title": "名詞",
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    "個人"
  ],
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        "盜賊"
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  "synonyms": [
    {
      "roman": "hánhster",
      "sense": "盜賊",
      "word": "га́нгстер"
    },
    {
      "roman": "rozbíjnyk",
      "sense": "盜賊",
      "word": "розбі́йник"
    }
  ],
  "tags": [
    "masculine"
  ],
  "word": "бандит"
}

Download raw JSONL data for бандит meaning in 烏克蘭語 (1.3kB)


This page is a part of the kaikki.org machine-readable 烏克蘭語 dictionary. This dictionary is based on structured data extracted on 2025-02-08 from the zhwiktionary dump dated 2025-02-02 using wiktextract (f90d964 and 9dbd323). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.