"congelo" meaning in 拉丁語

See congelo in All languages combined, or Wiktionary

Verb

Forms: congelō [canonical], congelāre, congelāvī, congelātum
Etymology: 源自 con- + gelō。
  1. 凍結在一起,凝結
    Sense id: zh-congelo-la-verb-xg4a1n~Y
  2. 變得僵硬 Tags: figuratively, intransitive
    Sense id: zh-congelo-la-verb-g~yVbAGT Categories (other): 拉丁語不及物動詞
  3. 使凝結;使僵硬
    Sense id: zh-congelo-la-verb-gQ6DgJz0
The following are not (yet) sense-disambiguated
Derived forms: congelātus, congelātiō
{
  "categories": [
    {
      "kind": "other",
      "name": "含有前綴con-的拉丁語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語動詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有5個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "word": "congelātus"
    },
    {
      "word": "congelātiō"
    }
  ],
  "descendants": [
    {
      "lang": "阿斯圖里亞斯語",
      "lang_code": "ast",
      "word": "conxelar"
    },
    {
      "lang": "加泰羅尼亞語",
      "lang_code": "ca",
      "word": "congelar"
    },
    {
      "lang": "英語",
      "lang_code": "en",
      "word": "congeal"
    },
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "congeler"
    },
    {
      "lang": "加利西亞語",
      "lang_code": "gl",
      "word": "conxelar"
    },
    {
      "lang": "意大利語",
      "lang_code": "it",
      "word": "congelare"
    },
    {
      "lang": "奧克語",
      "lang_code": "oc",
      "word": "congelar"
    },
    {
      "descendants": [
        {
          "lang": "佛得角克里奧爾語",
          "lang_code": "kea",
          "word": "konjela"
        }
      ],
      "lang": "葡萄牙語",
      "lang_code": "pt",
      "word": "congelar"
    },
    {
      "lang": "羅馬尼亞語",
      "lang_code": "ro",
      "word": "congela"
    },
    {
      "lang": "西西里語",
      "lang_code": "scn",
      "word": "gnilari"
    },
    {
      "lang": "西班牙語",
      "lang_code": "es",
      "word": "congelar"
    }
  ],
  "etymology_text": "源自 con- + gelō。",
  "forms": [
    {
      "form": "congelō",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "congelāre",
      "raw_tags": [
        "現在不定式"
      ]
    },
    {
      "form": "congelāvī",
      "raw_tags": [
        "完成主動式"
      ]
    },
    {
      "form": "congelātum",
      "raw_tags": [
        "目的動名詞"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "pos_title": "動詞",
  "senses": [
    {
      "glosses": [
        "凍結在一起,凝結"
      ],
      "id": "zh-congelo-la-verb-xg4a1n~Y"
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "拉丁語不及物動詞",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "變得僵硬"
      ],
      "id": "zh-congelo-la-verb-g~yVbAGT",
      "tags": [
        "figuratively",
        "intransitive"
      ]
    },
    {
      "glosses": [
        "使凝結;使僵硬"
      ],
      "id": "zh-congelo-la-verb-gQ6DgJz0"
    }
  ],
  "word": "congelo"
}
{
  "categories": [
    "含有前綴con-的拉丁語詞",
    "拉丁語動詞",
    "拉丁語詞元",
    "有5個詞條的頁面",
    "有詞條的頁面"
  ],
  "derived": [
    {
      "word": "congelātus"
    },
    {
      "word": "congelātiō"
    }
  ],
  "descendants": [
    {
      "lang": "阿斯圖里亞斯語",
      "lang_code": "ast",
      "word": "conxelar"
    },
    {
      "lang": "加泰羅尼亞語",
      "lang_code": "ca",
      "word": "congelar"
    },
    {
      "lang": "英語",
      "lang_code": "en",
      "word": "congeal"
    },
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "congeler"
    },
    {
      "lang": "加利西亞語",
      "lang_code": "gl",
      "word": "conxelar"
    },
    {
      "lang": "意大利語",
      "lang_code": "it",
      "word": "congelare"
    },
    {
      "lang": "奧克語",
      "lang_code": "oc",
      "word": "congelar"
    },
    {
      "descendants": [
        {
          "lang": "佛得角克里奧爾語",
          "lang_code": "kea",
          "word": "konjela"
        }
      ],
      "lang": "葡萄牙語",
      "lang_code": "pt",
      "word": "congelar"
    },
    {
      "lang": "羅馬尼亞語",
      "lang_code": "ro",
      "word": "congela"
    },
    {
      "lang": "西西里語",
      "lang_code": "scn",
      "word": "gnilari"
    },
    {
      "lang": "西班牙語",
      "lang_code": "es",
      "word": "congelar"
    }
  ],
  "etymology_text": "源自 con- + gelō。",
  "forms": [
    {
      "form": "congelō",
      "tags": [
        "canonical"
      ]
    },
    {
      "form": "congelāre",
      "raw_tags": [
        "現在不定式"
      ]
    },
    {
      "form": "congelāvī",
      "raw_tags": [
        "完成主動式"
      ]
    },
    {
      "form": "congelātum",
      "raw_tags": [
        "目的動名詞"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "pos_title": "動詞",
  "senses": [
    {
      "glosses": [
        "凍結在一起,凝結"
      ]
    },
    {
      "categories": [
        "拉丁語不及物動詞"
      ],
      "glosses": [
        "變得僵硬"
      ],
      "tags": [
        "figuratively",
        "intransitive"
      ]
    },
    {
      "glosses": [
        "使凝結;使僵硬"
      ]
    }
  ],
  "word": "congelo"
}

Download raw JSONL data for congelo meaning in 拉丁語 (1.6kB)


This page is a part of the kaikki.org machine-readable 拉丁語 dictionary. This dictionary is based on structured data extracted on 2025-08-11 from the zhwiktionary dump dated 2025-08-01 using wiktextract (7cef23e and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.