conformo in 拉丁語

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{
  "categories": [
    {
      "kind": "other",
      "name": "含有前綴con-的拉丁語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語動詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有5個詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "descendants": [
    {
      "lang": "加泰羅尼亞語",
      "lang_code": "ca",
      "word": "conformar"
    },
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "conformer"
    },
    {
      "lang": "加利西亞語",
      "lang_code": "gl",
      "word": "conformar"
    },
    {
      "lang": "意大利語",
      "lang_code": "it",
      "word": "conformare"
    },
    {
      "lang": "中古英語",
      "lang_code": "enm",
      "word": "conformen"
    },
    {
      "lang": "葡萄牙語",
      "lang_code": "pt",
      "word": "conformar"
    },
    {
      "lang": "羅馬尼亞語",
      "lang_code": "ro",
      "word": "conforma"
    },
    {
      "lang": "西班牙語",
      "lang_code": "es",
      "word": "conformar"
    }
  ],
  "etymology_text": "源自 con- + fōrmō。",
  "forms": [
    {
      "form": "cōnfōrmāre",
      "raw_tags": [
        "现在时不定式"
      ]
    },
    {
      "form": "cōnfōrmāvī",
      "raw_tags": [
        "完成时主动式"
      ]
    },
    {
      "form": "cōnfōrmātum",
      "raw_tags": [
        "目的动名词"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "（巧妙地）形成、塑造、構造"
      ],
      "id": "zh-conformo-la-verb-8p-~5IpF"
    },
    {
      "glosses": [
        "概述，描述"
      ],
      "id": "zh-conformo-la-verb-v7gkyoBD"
    }
  ],
  "word": "conformo"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "含有前綴con-的拉丁語詞",
    "拉丁語動詞",
    "拉丁語詞元",
    "有5個詞條的頁面"
  ],
  "descendants": [
    {
      "lang": "加泰羅尼亞語",
      "lang_code": "ca",
      "word": "conformar"
    },
    {
      "lang": "法語",
      "lang_code": "fr",
      "word": "conformer"
    },
    {
      "lang": "加利西亞語",
      "lang_code": "gl",
      "word": "conformar"
    },
    {
      "lang": "意大利語",
      "lang_code": "it",
      "word": "conformare"
    },
    {
      "lang": "中古英語",
      "lang_code": "enm",
      "word": "conformen"
    },
    {
      "lang": "葡萄牙語",
      "lang_code": "pt",
      "word": "conformar"
    },
    {
      "lang": "羅馬尼亞語",
      "lang_code": "ro",
      "word": "conforma"
    },
    {
      "lang": "西班牙語",
      "lang_code": "es",
      "word": "conformar"
    }
  ],
  "etymology_text": "源自 con- + fōrmō。",
  "forms": [
    {
      "form": "cōnfōrmāre",
      "raw_tags": [
        "现在时不定式"
      ]
    },
    {
      "form": "cōnfōrmāvī",
      "raw_tags": [
        "完成时主动式"
      ]
    },
    {
      "form": "cōnfōrmātum",
      "raw_tags": [
        "目的动名词"
      ]
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "（巧妙地）形成、塑造、構造"
      ]
    },
    {
      "glosses": [
        "概述，描述"
      ]
    }
  ],
  "word": "conformo"
}

This page is a part of the kaikki.org machine-readable 拉丁語 dictionary. This dictionary is based on structured data extracted on 2024-10-06 from the zhwiktionary dump dated 2024-10-02 using wiktextract (9f93753 and c1a3a36). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"conformo" meaning in 拉丁語

Verb