"abroganda" meaning in 拉丁語

See abroganda in All languages combined, or Wiktionary

Verb

  1. abrogandus 的屈折:
    主格/呼格陰性單數
    Tags: form-of Form of: abrogandus
    Sense id: zh-abroganda-la-verb-n68dwmxm
  2. abrogandus 的屈折:
    主格/賓格/呼格中性複數
    Tags: form-of Form of: abrogandus
    Sense id: zh-abroganda-la-verb-D2zZWGCy
The following are not (yet) sense-disambiguated

Verb

  1. abrogandus 的奪格陰性單數 Tags: form-of Form of: abrogandus
    Sense id: zh-abroganda-la-verb-fHQzDHGR
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "拉丁語分詞變格形",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語非詞元形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "pos_title": "分詞",
  "senses": [
    {
      "form_of": [
        {
          "word": "abrogandus"
        }
      ],
      "glosses": [
        "abrogandus 的屈折:",
        "主格/呼格陰性單數"
      ],
      "id": "zh-abroganda-la-verb-n68dwmxm",
      "tags": [
        "form-of"
      ]
    },
    {
      "form_of": [
        {
          "word": "abrogandus"
        }
      ],
      "glosses": [
        "abrogandus 的屈折:",
        "主格/賓格/呼格中性複數"
      ],
      "id": "zh-abroganda-la-verb-D2zZWGCy",
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "abroganda"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "拉丁語分詞變格形",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "拉丁語非詞元形式",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有詞條的頁面",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "pos_title": "分詞",
  "senses": [
    {
      "form_of": [
        {
          "word": "abrogandus"
        }
      ],
      "glosses": [
        "abrogandus 的奪格陰性單數"
      ],
      "id": "zh-abroganda-la-verb-fHQzDHGR",
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "abroganda"
}
{
  "categories": [
    "拉丁語分詞變格形",
    "拉丁語非詞元形式",
    "有1個詞條的頁面",
    "有詞條的頁面"
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "pos_title": "分詞",
  "senses": [
    {
      "form_of": [
        {
          "word": "abrogandus"
        }
      ],
      "glosses": [
        "abrogandus 的屈折:",
        "主格/呼格陰性單數"
      ],
      "tags": [
        "form-of"
      ]
    },
    {
      "form_of": [
        {
          "word": "abrogandus"
        }
      ],
      "glosses": [
        "abrogandus 的屈折:",
        "主格/賓格/呼格中性複數"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "abroganda"
}

{
  "categories": [
    "拉丁語分詞變格形",
    "拉丁語非詞元形式",
    "有1個詞條的頁面",
    "有詞條的頁面"
  ],
  "lang": "拉丁語",
  "lang_code": "la",
  "pos": "verb",
  "pos_title": "分詞",
  "senses": [
    {
      "form_of": [
        {
          "word": "abrogandus"
        }
      ],
      "glosses": [
        "abrogandus 的奪格陰性單數"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "abroganda"
}

Download raw JSONL data for abroganda meaning in 拉丁語 (0.9kB)


This page is a part of the kaikki.org machine-readable 拉丁語 dictionary. This dictionary is based on structured data extracted on 2025-01-31 from the zhwiktionary dump dated 2025-01-20 using wiktextract (bcd5c38 and 9dbd323). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.