"Сократ" meaning in 俄語

See Сократ in All languages combined, or Wiktionary

Proper name

Forms: Sokrát [romanization], Сокра́та, Сокра́ты [nominative plural], Сокра́тов [genitive plural], сокра́товский, сократи́ческий
Etymology: 借自古希臘語 Σωκράτης (Sōkrátēs)。
  1. 蘇格拉底
    Sense id: zh-Сократ-ru-name-c4acD24m
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "俄語 個人",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語 古希臘",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語 哲學家",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語專有名詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "俄語詞元",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "有1個詞條的頁面",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "派生自古希臘語的俄語詞",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "源自古希臘語的俄語借詞",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "借自古希臘語 Σωκράτης (Sōkrátēs)。",
  "forms": [
    {
      "form": "Sokrát",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "Сокра́та",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "Сокра́ты",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "Сокра́тов",
      "tags": [
        "genitive plural"
      ]
    },
    {
      "form": "сокра́товский",
      "raw_tags": [
        "關係形容詞"
      ]
    },
    {
      "form": "сократи́ческий",
      "raw_tags": [
        "關係形容詞"
      ]
    }
  ],
  "lang": "俄語",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "蘇格拉底"
      ],
      "id": "zh-Сократ-ru-name-c4acD24m"
    }
  ],
  "tags": [
    "animate",
    "masculine"
  ],
  "word": "Сократ"
}
{
  "categories": [
    "俄語 個人",
    "俄語 古希臘",
    "俄語 哲學家",
    "俄語專有名詞",
    "俄語詞元",
    "有1個詞條的頁面",
    "派生自古希臘語的俄語詞",
    "源自古希臘語的俄語借詞"
  ],
  "etymology_text": "借自古希臘語 Σωκράτης (Sōkrátēs)。",
  "forms": [
    {
      "form": "Sokrát",
      "tags": [
        "romanization"
      ]
    },
    {
      "form": "Сокра́та",
      "raw_tags": [
        "屬格"
      ]
    },
    {
      "form": "Сокра́ты",
      "tags": [
        "nominative plural"
      ]
    },
    {
      "form": "Сокра́тов",
      "tags": [
        "genitive plural"
      ]
    },
    {
      "form": "сокра́товский",
      "raw_tags": [
        "關係形容詞"
      ]
    },
    {
      "form": "сократи́ческий",
      "raw_tags": [
        "關係形容詞"
      ]
    }
  ],
  "lang": "俄語",
  "lang_code": "ru",
  "pos": "name",
  "senses": [
    {
      "glosses": [
        "蘇格拉底"
      ]
    }
  ],
  "tags": [
    "animate",
    "masculine"
  ],
  "word": "Сократ"
}

Download raw JSONL data for Сократ meaning in 俄語 (0.8kB)


This page is a part of the kaikki.org machine-readable 俄語 dictionary. This dictionary is based on structured data extracted on 2024-10-03 from the zhwiktionary dump dated 2024-10-02 using wiktextract (593e81e and 59b8406). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.