"albergatore" meaning in Итальянский

See albergatore in All languages combined, or Wiktionary

Noun

IPA: albergaˈtore
Etymology: От ??
  1. хозяин постоялого двора Tags: obsolete
    Sense id: ru-albergatore-it-noun-r6YdOxCh Categories (other): Устаревшие выражения/it
  2. владелец гостиницы
    Sense id: ru-albergatore-it-noun-jLY-C8X~
The following are not (yet) sense-disambiguated
Related terms: albergo, albergare
{
  "categories": [
    {
      "kind": "other",
      "name": "Итальянские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Итальянский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Мужской род/it",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 11 букв/it",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/it",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "hyphenation": "albergatore",
  "lang": "Итальянский",
  "lang_code": "it",
  "pos": "noun",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "существительные"
      ],
      "word": "albergo"
    },
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "albergare"
    }
  ],
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Устаревшие выражения/it",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "хозяин постоялого двора"
      ],
      "id": "ru-albergatore-it-noun-r6YdOxCh",
      "tags": [
        "obsolete"
      ]
    },
    {
      "glosses": [
        "владелец гостиницы"
      ],
      "id": "ru-albergatore-it-noun-jLY-C8X~"
    }
  ],
  "sounds": [
    {
      "ipa": "albergaˈtore"
    }
  ],
  "word": "albergatore"
}
{
  "categories": [
    "Итальянские существительные",
    "Итальянский язык",
    "Мужской род/it",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Слова из 11 букв/it",
    "Требуется категоризация/it"
  ],
  "etymology_text": "От ??",
  "hyphenation": "albergatore",
  "lang": "Итальянский",
  "lang_code": "it",
  "pos": "noun",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "существительные"
      ],
      "word": "albergo"
    },
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "albergare"
    }
  ],
  "senses": [
    {
      "categories": [
        "Устаревшие выражения/it"
      ],
      "glosses": [
        "хозяин постоялого двора"
      ],
      "tags": [
        "obsolete"
      ]
    },
    {
      "glosses": [
        "владелец гостиницы"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "albergaˈtore"
    }
  ],
  "word": "albergatore"
}

Download raw JSONL data for albergatore meaning in Итальянский (0.9kB)


This page is a part of the kaikki.org machine-readable Итальянский dictionary. This dictionary is based on structured data extracted on 2025-06-07 from the ruwiktionary dump dated 2025-06-01 using wiktextract (92124b4 and f1c2b61). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.