"fremor" meaning in All languages combined

See fremor on Wiktionary

Noun [Латинский]

Etymology: От ??
  1. рычание, рёв
    Sense id: ru-fremor-la-noun-WpvxqEwu
The following are not (yet) sense-disambiguated

Noun [Старофранцузский]

Etymology: Происходит от ??
  1. шум
    Sense id: ru-fremor-fro-noun-rZJvLHhJ
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "Звуки/la",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Латинские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Латинский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Мужской род/la",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 6 букв/la",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "lang": "Латинский",
  "lang_code": "la",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "рычание, рёв"
      ],
      "id": "ru-fremor-la-noun-WpvxqEwu"
    }
  ],
  "word": "fremor"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Женский род/fro",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 6 букв/fro",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Старофранцузские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Старофранцузский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/fro",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Происходит от ??",
  "lang": "Старофранцузский",
  "lang_code": "fro",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "шум"
      ],
      "id": "ru-fremor-fro-noun-rZJvLHhJ"
    }
  ],
  "word": "fremor"
}
{
  "categories": [
    "Звуки/la",
    "Латинские существительные",
    "Латинский язык",
    "Мужской род/la",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Слова из 6 букв/la"
  ],
  "etymology_text": "От ??",
  "lang": "Латинский",
  "lang_code": "la",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "рычание, рёв"
      ]
    }
  ],
  "word": "fremor"
}

{
  "categories": [
    "Женский род/fro",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Слова из 6 букв/fro",
    "Старофранцузские существительные",
    "Старофранцузский язык",
    "Требуется категоризация/fro"
  ],
  "etymology_text": "Происходит от ??",
  "lang": "Старофранцузский",
  "lang_code": "fro",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "шум"
      ]
    }
  ],
  "word": "fremor"
}

Download raw JSONL data for fremor meaning in All languages combined (0.9kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-03 from the ruwiktionary dump dated 2024-10-20 using wiktextract (d6bf104 and a5af179). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.