"anibersaryo" meaning in All languages combined

See anibersaryo on Wiktionary

Noun [Себуано]

Etymology: От ??
  1. годовщина
    Sense id: ru-anibersaryo-ceb-noun-nRTm7F9u
The following are not (yet) sense-disambiguated

Noun [Тагальский]

Etymology: От ??
  1. годовщина
    Sense id: ru-anibersaryo-tl-noun-nRTm7F9u
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "Год/ceb",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Себуано",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 11 букв/ceb",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Существительные себуано",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "lang": "Себуано",
  "lang_code": "ceb",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "годовщина"
      ],
      "id": "ru-anibersaryo-ceb-noun-nRTm7F9u"
    }
  ],
  "word": "anibersaryo"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Викисловарь:Статьи с межъязыковой омонимией",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Год/tl",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 11 букв/tl",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Тагальские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Тагальский язык",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "lang": "Тагальский",
  "lang_code": "tl",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "годовщина"
      ],
      "id": "ru-anibersaryo-tl-noun-nRTm7F9u"
    }
  ],
  "word": "anibersaryo"
}
{
  "categories": [
    "Год/ceb",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Себуано",
    "Слова из 11 букв/ceb",
    "Существительные себуано"
  ],
  "etymology_text": "От ??",
  "lang": "Себуано",
  "lang_code": "ceb",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "годовщина"
      ]
    }
  ],
  "word": "anibersaryo"
}

{
  "categories": [
    "Викисловарь:Статьи с межъязыковой омонимией",
    "Год/tl",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Слова из 11 букв/tl",
    "Тагальские существительные",
    "Тагальский язык"
  ],
  "etymology_text": "От ??",
  "lang": "Тагальский",
  "lang_code": "tl",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "годовщина"
      ]
    }
  ],
  "word": "anibersaryo"
}

Download raw JSONL data for anibersaryo meaning in All languages combined (0.9kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-28 from the ruwiktionary dump dated 2024-11-21 using wiktextract (65a6e81 and 0dbea76). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.