"abonnere" meaning in All languages combined

See abonnere on Wiktionary

Verb [Датский]

Etymology: Из ??
  1. абонировать
    Sense id: ru-abonnere-da-verb-igBNkP~R
The following are not (yet) sense-disambiguated

Verb [Норвежский]

Etymology: Из ??
  1. абонировать
    Sense id: ru-abonnere-no-verb-igBNkP~R
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "Датские глаголы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Датский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 8 букв/da",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/da",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Из ??",
  "lang": "Датский",
  "lang_code": "da",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "абонировать"
      ],
      "id": "ru-abonnere-da-verb-igBNkP~R"
    }
  ],
  "word": "abonnere"
}

{
  "categories": [
    {
      "kind": "other",
      "name": "Викисловарь:Статьи с межъязыковой омонимией",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Норвежские глаголы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Норвежский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 8 букв/no",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/no",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Из ??",
  "lang": "Норвежский",
  "lang_code": "no",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "абонировать"
      ],
      "id": "ru-abonnere-no-verb-igBNkP~R"
    }
  ],
  "word": "abonnere"
}
{
  "categories": [
    "Датские глаголы",
    "Датский язык",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Слова из 8 букв/da",
    "Требуется категоризация/da"
  ],
  "etymology_text": "Из ??",
  "lang": "Датский",
  "lang_code": "da",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "абонировать"
      ]
    }
  ],
  "word": "abonnere"
}

{
  "categories": [
    "Викисловарь:Статьи с межъязыковой омонимией",
    "Нет сведений о составе слова",
    "Норвежские глаголы",
    "Норвежский язык",
    "Нужна этимология",
    "Слова из 8 букв/no",
    "Требуется категоризация/no"
  ],
  "etymology_text": "Из ??",
  "lang": "Норвежский",
  "lang_code": "no",
  "pos": "verb",
  "senses": [
    {
      "glosses": [
        "абонировать"
      ]
    }
  ],
  "word": "abonnere"
}

Download raw JSONL data for abonnere meaning in All languages combined (0.9kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-09-27 from the ruwiktionary dump dated 2024-09-20 using wiktextract (3f344ef and 66545a6). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.