"сдоивший" meaning in All languages combined

See сдоивший on Wiktionary

Verb [Русский]

IPA: zdɐˈifʂɨɪ̯
Etymology: Происходит от ??
  1. действ. прич. прош. вр. от сдоить
    Sense id: ru-сдоивший-ru-verb-K7u59XEK
The following are not (yet) sense-disambiguated
Related terms: сдоить
{
  "categories": [
    {
      "kind": "other",
      "name": "Нет сведений о составе слова/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Причастия, склонение 4a",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские причастия",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 8 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Происходит от ??",
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "verb",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "сдоить"
    }
  ],
  "senses": [
    {
      "glosses": [
        "действ. прич. прош. вр. от сдоить"
      ],
      "id": "ru-сдоивший-ru-verb-K7u59XEK"
    }
  ],
  "sounds": [
    {
      "ipa": "zdɐˈifʂɨɪ̯"
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "сдоивший"
}
{
  "categories": [
    "Нет сведений о составе слова/ru",
    "Нужна этимология",
    "Причастия, склонение 4a",
    "Русские причастия",
    "Русский язык",
    "Слова из 8 букв/ru",
    "Требуется категоризация/ru"
  ],
  "etymology_text": "Происходит от ??",
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "verb",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "сдоить"
    }
  ],
  "senses": [
    {
      "glosses": [
        "действ. прич. прош. вр. от сдоить"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "zdɐˈifʂɨɪ̯"
    }
  ],
  "tags": [
    "participle"
  ],
  "word": "сдоивший"
}

Download raw JSONL data for сдоивший meaning in All languages combined (0.7kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-11-06 from the ruwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.