сверхрекорд in All languages combined

IPA: ˌsvʲerxrʲɪˈkort [Show additional information ▼] [Hide additional information ▲]

Etymology: От ?? Forms: свѐрхреко́рд [nominative, singular], свѐрхреко́рды [nominative, plural], свѐрхреко́рда [genitive, singular], свѐрхреко́рдов [genitive, plural], свѐрхреко́рду [dative, singular], свѐрхреко́рдам [dative, plural], свѐрхреко́рд [accusative, singular], свѐрхреко́рды [accusative, plural], свѐрхреко́рдом [instrumental, singular], свѐрхреко́рдами [instrumental, plural], свѐрхреко́рде [prepositional, singular], свѐрхреко́рдах [prepositional, plural]

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "Мужской род/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Неодушевлённые/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские лексемы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова с приставкой сверх-",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова, тип морфемного строения pr-R",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные, склонение 1a",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 11 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "свѐрхреко́рд",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рды",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рда",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдов",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рду",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рд",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рды",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рдом",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рде",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "необычайно высокий показатель, достигнутый в состязании или в работе"
      ],
      "id": "ru-сверхрекорд-ru-noun-PwAs-wj4"
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsvʲerxrʲɪˈkort"
    }
  ],
  "tags": [
    "declension-2",
    "inanimate",
    "masculine"
  ],
  "word": "сверхрекорд"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "Мужской род/ru",
    "Неодушевлённые/ru",
    "Нужна этимология",
    "Русские лексемы",
    "Русские слова с приставкой сверх-",
    "Русские слова, тип морфемного строения pr-R",
    "Русские существительные",
    "Русские существительные, склонение 1a",
    "Русский язык",
    "Слова из 11 букв/ru",
    "Требуется категоризация/ru"
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "свѐрхреко́рд",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рды",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рда",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдов",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рду",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рд",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рды",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рдом",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "свѐрхреко́рде",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "свѐрхреко́рдах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "необычайно высокий показатель, достигнутый в состязании или в работе"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsvʲerxrʲɪˈkort"
    }
  ],
  "tags": [
    "declension-2",
    "inanimate",
    "masculine"
  ],
  "word": "сверхрекорд"
}

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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the ruwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"сверхрекорд" meaning in All languages combined

Noun [Русский]