замгендиректора in All languages combined

IPA: ˌzamˌɡʲenʲdʲɪˈrʲektərə [Show additional information ▼] [Hide additional information ▲]

Etymology: Происходит от ?? Forms: за̀мгѐндире́ктора [nominative, singular], за̀мгѐндире́ктора [nominative, plural], за̀мгѐндире́ктора [genitive, singular], за̀мгѐндире́ктора [genitive, plural], за̀мгѐндире́ктора [dative, singular], за̀мгѐндире́ктора [dative, plural], за̀мгѐндире́ктора [accusative, singular], за̀мгѐндире́ктора [accusative, plural], за̀мгѐндире́ктора [instrumental, singular], за̀мгѐндире́ктора [instrumental, plural], за̀мгѐндире́ктора [prepositional, singular], за̀мгѐндире́ктора [prepositional, plural]

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "Несклоняемые существительные/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Общий род/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Одушевлённые/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские лексемы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 15 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Происходит от ??",
  "forms": [
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "замдиректора"
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "заместитель генерального директора"
      ],
      "id": "ru-замгендиректора-ru-noun-HHEuCexT"
    }
  ],
  "sounds": [
    {
      "ipa": "ˌzamˌɡʲenʲdʲɪˈrʲektərə"
    }
  ],
  "tags": [
    "animate",
    "common"
  ],
  "word": "замгендиректора"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "Несклоняемые существительные/ru",
    "Нет сведений о составе слова/ru",
    "Нужна этимология",
    "Общий род/ru",
    "Одушевлённые/ru",
    "Русские лексемы",
    "Русские существительные",
    "Русский язык",
    "Слова из 15 букв/ru",
    "Требуется категоризация/ru"
  ],
  "etymology_text": "Происходит от ??",
  "forms": [
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "за̀мгѐндире́ктора",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "замдиректора"
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "заместитель генерального директора"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˌzamˌɡʲenʲdʲɪˈrʲektərə"
    }
  ],
  "tags": [
    "animate",
    "common"
  ],
  "word": "замгендиректора"
}

Download raw JSONL data for замгендиректора meaning in All languages combined (1.8kB)

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the ruwiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"замгендиректора" meaning in All languages combined

Noun [Русский]