"Фрейд" meaning in All languages combined

See Фрейд on Wiktionary

Proper name [Русский]

IPA: frʲeɪ̯t
Etymology: От ??
  1. немецкая фамилия
    Sense id: ru-Фрейд-ru-name-bp-ok51X
The following are not (yet) sense-disambiguated
Synonyms: Фрёйд, Фройд Hypernyms: фамилия Related terms: фрейдизм, фрейдовский Translations: Freud (Английский), Freud (Немецкий)
{
  "categories": [
    {
      "kind": "other",
      "name": "Немецкие фамилии/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские лексемы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова, тип морфемного строения R",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 5 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Фамилии/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "фамилия"
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "name",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "существительные"
      ],
      "word": "фрейдизм"
    },
    {
      "raw_tags": [
        "Ближайшее родство",
        "прилагательные"
      ],
      "word": "фрейдовский"
    }
  ],
  "senses": [
    {
      "glosses": [
        "немецкая фамилия"
      ],
      "id": "ru-Фрейд-ru-name-bp-ok51X"
    }
  ],
  "sounds": [
    {
      "ipa": "frʲeɪ̯t"
    }
  ],
  "synonyms": [
    {
      "sense_index": 1,
      "word": "Фрёйд"
    },
    {
      "sense_index": 1,
      "word": "Фройд"
    }
  ],
  "translations": [
    {
      "lang": "Английский",
      "lang_code": "en",
      "word": "Freud"
    },
    {
      "lang": "Немецкий",
      "lang_code": "de",
      "word": "Freud"
    }
  ],
  "word": "Фрейд"
}
{
  "categories": [
    "Немецкие фамилии/ru",
    "Нужна этимология",
    "Русские лексемы",
    "Русские слова, тип морфемного строения R",
    "Русский язык",
    "Слова из 5 букв/ru",
    "Фамилии/ru"
  ],
  "etymology_text": "От ??",
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "фамилия"
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "name",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "существительные"
      ],
      "word": "фрейдизм"
    },
    {
      "raw_tags": [
        "Ближайшее родство",
        "прилагательные"
      ],
      "word": "фрейдовский"
    }
  ],
  "senses": [
    {
      "glosses": [
        "немецкая фамилия"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "frʲeɪ̯t"
    }
  ],
  "synonyms": [
    {
      "sense_index": 1,
      "word": "Фрёйд"
    },
    {
      "sense_index": 1,
      "word": "Фройд"
    }
  ],
  "translations": [
    {
      "lang": "Английский",
      "lang_code": "en",
      "word": "Freud"
    },
    {
      "lang": "Немецкий",
      "lang_code": "de",
      "word": "Freud"
    }
  ],
  "word": "Фрейд"
}

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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-01-13 from the ruwiktionary dump dated 2025-01-01 using wiktextract (4ba5975 and 4ed51a5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.