Збруев in All languages combined

IPA: ˈzbru(ɪ̯)ɪf [singular], ˈzbru(ɪ̯)ɪvɨ [plural] [Show additional information ▼] [Hide additional information ▲]

Etymology: От ?? Forms: Збру́ев [nominative, singular], Збру́ева [nominative, plural], Збру́евы [nominative, masculine], Збру́ева [genitive, singular], Збру́евой [genitive, plural], Збру́евых [genitive, masculine], Збру́еву [dative, singular], Збру́евой [dative, plural], Збру́евым [dative, masculine], Збру́ева [accusative, singular], Збру́еву [accusative, plural], Збру́евых [accusative, masculine], Збру́евым [instrumental, singular], Збру́евой [instrumental, plural], Збру́евыми [instrumental, masculine], Збру́еве [prepositional, singular], Збру́евой [prepositional, plural], Збру́евых [prepositional, masculine]

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские лексемы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова, тип морфемного строения R",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные, местоименное склонение",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские фамилии/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 6 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Фамилии/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "Збру́ев",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "Збру́ева",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "Збру́евы",
      "tags": [
        "nominative",
        "masculine"
      ]
    },
    {
      "form": "Збру́ева",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "Збру́евых",
      "tags": [
        "genitive",
        "masculine"
      ]
    },
    {
      "form": "Збру́еву",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "Збру́евым",
      "tags": [
        "dative",
        "masculine"
      ]
    },
    {
      "form": "Збру́ева",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "Збру́еву",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "Збру́евых",
      "tags": [
        "accusative",
        "masculine"
      ]
    },
    {
      "form": "Збру́евым",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "Збру́евыми",
      "tags": [
        "instrumental",
        "masculine"
      ]
    },
    {
      "form": "Збру́еве",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "prepositional",
        "plural"
      ]
    },
    {
      "form": "Збру́евых",
      "tags": [
        "prepositional",
        "masculine"
      ]
    }
  ],
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "фамилия"
    }
  ],
  "hyphenations": [
    {
      "parts": [
        "Збру́",
        "ев"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "name",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "прилагательные"
      ],
      "word": "збруевский"
    }
  ],
  "senses": [
    {
      "examples": [
        {
          "author": "Владимир Гиляровский",
          "bold_text_offsets": [
            [
              89,
              95
            ]
          ],
          "date": "1934",
          "ref": "В. А. Гиляровский, «Москва газетная», 1934 г. [НКРЯ]",
          "source": "НКРЯ",
          "text": "Самыми хлёсткими сотрудниками, делавшими успех газеты в розницу, были фельетонисты П. А. Збруев, чиновник особых поручений при секретном отделении обер-полицмейстера, благодаря своей службе знавший все тайны Москвы, и Н. И. Пастухов.",
          "title": "Москва газетная"
        }
      ],
      "glosses": [
        "русская фамилия"
      ],
      "id": "ru-Збруев-ru-name-hwhw-Udo"
    }
  ],
  "sounds": [
    {
      "ipa": "ˈzbru(ɪ̯)ɪf",
      "tags": [
        "singular"
      ]
    },
    {
      "ipa": "ˈzbru(ɪ̯)ɪvɨ",
      "tags": [
        "plural"
      ]
    }
  ],
  "tags": [
    "animate",
    "pronominal"
  ],
  "word": "Збруев"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "Нужна этимология",
    "Русские лексемы",
    "Русские слова, тип морфемного строения R",
    "Русские существительные, местоименное склонение",
    "Русские фамилии/ru",
    "Русский язык",
    "Слова из 6 букв/ru",
    "Фамилии/ru"
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "Збру́ев",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "Збру́ева",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "Збру́евы",
      "tags": [
        "nominative",
        "masculine"
      ]
    },
    {
      "form": "Збру́ева",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "Збру́евых",
      "tags": [
        "genitive",
        "masculine"
      ]
    },
    {
      "form": "Збру́еву",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "Збру́евым",
      "tags": [
        "dative",
        "masculine"
      ]
    },
    {
      "form": "Збру́ева",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "Збру́еву",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "Збру́евых",
      "tags": [
        "accusative",
        "masculine"
      ]
    },
    {
      "form": "Збру́евым",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "Збру́евыми",
      "tags": [
        "instrumental",
        "masculine"
      ]
    },
    {
      "form": "Збру́еве",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "Збру́евой",
      "tags": [
        "prepositional",
        "plural"
      ]
    },
    {
      "form": "Збру́евых",
      "tags": [
        "prepositional",
        "masculine"
      ]
    }
  ],
  "hypernyms": [
    {
      "sense_index": 1,
      "word": "фамилия"
    }
  ],
  "hyphenations": [
    {
      "parts": [
        "Збру́",
        "ев"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "name",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "прилагательные"
      ],
      "word": "збруевский"
    }
  ],
  "senses": [
    {
      "examples": [
        {
          "author": "Владимир Гиляровский",
          "bold_text_offsets": [
            [
              89,
              95
            ]
          ],
          "date": "1934",
          "ref": "В. А. Гиляровский, «Москва газетная», 1934 г. [НКРЯ]",
          "source": "НКРЯ",
          "text": "Самыми хлёсткими сотрудниками, делавшими успех газеты в розницу, были фельетонисты П. А. Збруев, чиновник особых поручений при секретном отделении обер-полицмейстера, благодаря своей службе знавший все тайны Москвы, и Н. И. Пастухов.",
          "title": "Москва газетная"
        }
      ],
      "glosses": [
        "русская фамилия"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˈzbru(ɪ̯)ɪf",
      "tags": [
        "singular"
      ]
    },
    {
      "ipa": "ˈzbru(ɪ̯)ɪvɨ",
      "tags": [
        "plural"
      ]
    }
  ],
  "tags": [
    "animate",
    "pronominal"
  ],
  "word": "Збруев"
}

Download raw JSONL data for Збруев meaning in All languages combined (2.8kB)

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-08-09 from the ruwiktionary dump dated 2025-08-03 using wiktextract (99a4ed9 and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"Збруев" meaning in All languages combined

Proper name [Русский]