суперлогарифм in Русский

IPA: ˌsupʲɪrɫəɡɐˈrʲifm [Show additional information ▼] [Hide additional information ▲]

Etymology: От ?? Forms: су̀перлогари́фм [nominative, singular], су̀перлогари́фмы [nominative, plural], су̀перлогари́фма [genitive, singular], су̀перлогари́фмов [genitive, plural], су̀перлогари́фму [dative, singular], су̀перлогари́фмам [dative, plural], су̀перлогари́фм [accusative, singular], су̀перлогари́фмы [accusative, plural], су̀перлогари́фмом [instrumental, singular], су̀перлогари́фмами [instrumental, plural], су̀перлогари́фме [prepositional, singular], су̀перлогари́фмах [prepositional, plural]

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "Мужской род/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Неодушевлённые/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские лексемы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова с приставкой супер-",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова, тип морфемного строения pr-R",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные, склонение 1a",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 13 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "су̀перлогари́фм",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмы",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фма",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмов",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фму",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фм",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмы",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фмом",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фме",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "показатель тетрации основания a, при котором получается число b"
      ],
      "id": "ru-суперлогарифм-ru-noun-yxLXrQ5G",
      "raw_glosses": [
        "матем. показатель тетрации основания a, при котором получается число b"
      ],
      "topics": [
        "mathematics"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsupʲɪrɫəɡɐˈrʲifm"
    }
  ],
  "tags": [
    "declension-2",
    "inanimate",
    "masculine"
  ],
  "word": "суперлогарифм"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "Мужской род/ru",
    "Неодушевлённые/ru",
    "Нужна этимология",
    "Русские лексемы",
    "Русские слова с приставкой супер-",
    "Русские слова, тип морфемного строения pr-R",
    "Русские существительные",
    "Русские существительные, склонение 1a",
    "Русский язык",
    "Слова из 13 букв/ru",
    "Требуется категоризация/ru"
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "су̀перлогари́фм",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмы",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фма",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмов",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фму",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фм",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмы",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фмом",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "су̀перлогари́фме",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "су̀перлогари́фмах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "показатель тетрации основания a, при котором получается число b"
      ],
      "raw_glosses": [
        "матем. показатель тетрации основания a, при котором получается число b"
      ],
      "topics": [
        "mathematics"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsupʲɪrɫəɡɐˈrʲifm"
    }
  ],
  "tags": [
    "declension-2",
    "inanimate",
    "masculine"
  ],
  "word": "суперлогарифм"
}

Download raw JSONL data for суперлогарифм meaning in Русский (2.0kB)

This page is a part of the kaikki.org machine-readable Русский dictionary. This dictionary is based on structured data extracted on 2024-11-06 from the ruwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"суперлогарифм" meaning in Русский

Noun