супергроссмейстер in Русский

IPA: ˌsupʲɪrɡrɐˈsmʲeɪ̯sʲtʲɪr [Show additional information ▼] [Hide additional information ▲]

Etymology: От ?? Forms: су̀пергроссме́йстер [nominative, singular], су̀пергроссме́йстеры [nominative, plural], су̀пергроссме́йстера [genitive, singular], су̀пергроссме́йстеров [genitive, plural], су̀пергроссме́йстеру [dative, singular], су̀пергроссме́йстерам [dative, plural], су̀пергроссме́йстера [accusative, singular], су̀пергроссме́йстеров [accusative, plural], су̀пергроссме́йстером [instrumental, singular], су̀пергроссме́йстерами [instrumental, plural], су̀пергроссме́йстере [prepositional, singular], су̀пергроссме́йстерах [prepositional, plural]

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "Мужской род/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Одушевлённые/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские лексемы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова с приставкой супер-",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские слова, тип морфемного строения pr-R-R",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные, склонение 1a",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 17 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "су̀пергроссме́йстер",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстеры",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстера",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстеров",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстеру",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстерам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстера",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстеров",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстером",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстерами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстере",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстерах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "гроссмейстер высшего класса"
      ],
      "id": "ru-супергроссмейстер-ru-noun-hMF5RmAw"
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsupʲɪrɡrɐˈsmʲeɪ̯sʲtʲɪr"
    }
  ],
  "tags": [
    "animate",
    "declension-2",
    "masculine"
  ],
  "word": "супергроссмейстер"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "Мужской род/ru",
    "Нужна этимология",
    "Одушевлённые/ru",
    "Русские лексемы",
    "Русские слова с приставкой супер-",
    "Русские слова, тип морфемного строения pr-R-R",
    "Русские существительные",
    "Русские существительные, склонение 1a",
    "Русский язык",
    "Слова из 17 букв/ru",
    "Требуется категоризация/ru"
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "су̀пергроссме́йстер",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстеры",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстера",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстеров",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстеру",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстерам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстера",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстеров",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстером",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстерами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "су̀пергроссме́йстере",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "су̀пергроссме́йстерах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "гроссмейстер высшего класса"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsupʲɪrɡrɐˈsmʲeɪ̯sʲtʲɪr"
    }
  ],
  "tags": [
    "animate",
    "declension-2",
    "masculine"
  ],
  "word": "супергроссмейстер"
}

Download raw JSONL data for супергроссмейстер meaning in Русский (1.9kB)

This page is a part of the kaikki.org machine-readable Русский dictionary. This dictionary is based on structured data extracted on 2025-01-27 from the ruwiktionary dump dated 2025-01-20 using wiktextract (c7bdf0e and 5c11237). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"супергроссмейстер" meaning in Русский

Noun