"исказнив" meaning in Русский

See исказнив in All languages combined, or Wiktionary

Verb

IPA: ɪskɐˈzʲnʲif
Etymology: От исказнить, далее от ??
  1. дееприч. от исказнить
    Sense id: ru-исказнив-ru-verb-6vhJ11AN
The following are not (yet) sense-disambiguated
Synonyms: исказнивши Related terms: исказнить
{
  "categories": [
    {
      "kind": "other",
      "name": "Невозвратные русские деепричастия",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские деепричастия",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские деепричастия совершенного вида",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 8 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От исказнить, далее от ??",
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "verb",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "исказнить"
    }
  ],
  "senses": [
    {
      "glosses": [
        "дееприч. от исказнить"
      ],
      "id": "ru-исказнив-ru-verb-6vhJ11AN"
    }
  ],
  "sounds": [
    {
      "ipa": "ɪskɐˈzʲnʲif"
    }
  ],
  "synonyms": [
    {
      "sense_index": 1,
      "word": "исказнивши"
    }
  ],
  "tags": [
    "gerund",
    "participle"
  ],
  "word": "исказнив"
}
{
  "categories": [
    "Невозвратные русские деепричастия",
    "Нет сведений о составе слова/ru",
    "Нужна этимология",
    "Русские деепричастия",
    "Русские деепричастия совершенного вида",
    "Русский язык",
    "Слова из 8 букв/ru",
    "Требуется категоризация/ru"
  ],
  "etymology_text": "От исказнить, далее от ??",
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "verb",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "исказнить"
    }
  ],
  "senses": [
    {
      "glosses": [
        "дееприч. от исказнить"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ɪskɐˈzʲnʲif"
    }
  ],
  "synonyms": [
    {
      "sense_index": 1,
      "word": "исказнивши"
    }
  ],
  "tags": [
    "gerund",
    "participle"
  ],
  "word": "исказнив"
}

Download raw JSONL data for исказнив meaning in Русский (0.9kB)


This page is a part of the kaikki.org machine-readable Русский dictionary. This dictionary is based on structured data extracted on 2025-07-19 from the ruwiktionary dump dated 2025-07-02 using wiktextract (45c4a21 and f1c2b61). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.