See zandj in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "Лимбургские существительные", "parents": [], "source": "w" }, { "kind": "other", "name": "Лимбургский язык", "parents": [], "source": "w" }, { "kind": "other", "name": "Нет сведений о составе слова", "parents": [], "source": "w" }, { "kind": "other", "name": "Нужна этимология", "parents": [], "source": "w" }, { "kind": "other", "name": "Песок/li", "parents": [], "source": "w" }, { "kind": "other", "name": "Слова из 5 букв/li", "parents": [], "source": "w" } ], "etymology_text": "От ??", "lang": "Лимбургский", "lang_code": "li", "pos": "noun", "senses": [ { "glosses": [ "песок" ], "id": "ru-zandj-li-noun-Jsb4Vg0k" } ], "word": "zandj" }
{ "categories": [ "Лимбургские существительные", "Лимбургский язык", "Нет сведений о составе слова", "Нужна этимология", "Песок/li", "Слова из 5 букв/li" ], "etymology_text": "От ??", "lang": "Лимбургский", "lang_code": "li", "pos": "noun", "senses": [ { "glosses": [ "песок" ] } ], "word": "zandj" }
Download raw JSONL data for zandj meaning in Лимбургский (0.4kB)
This page is a part of the kaikki.org machine-readable Лимбургский dictionary. This dictionary is based on structured data extracted on 2024-12-10 from the ruwiktionary dump dated 2024-12-04 using wiktextract (ea2043b and fc9d713). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.