"swashbuckler" meaning in Английский

See swashbuckler in All languages combined, or Wiktionary

Noun

IPA: ˈswɔʃˌbʌklə Forms: swashbuckler [singular], swashbucklers [plural]
Etymology: От ??
  1. головорез, сорвиголова
    Sense id: ru-swashbuckler-en-noun-dF2LvsWl
  2. боевик, произведение приключенческого жанра (с головорезом в качестве главного героя или действующего лица)
    Sense id: ru-swashbuckler-en-noun-I-SMoZkQ
  3. хвастун, бахвал
    Sense id: ru-swashbuckler-en-noun-DB6bFs5U
The following are not (yet) sense-disambiguated
Related terms: swashbuckling, swashbuckle
{
  "categories": [
    {
      "kind": "other",
      "name": "Английские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Английский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Плохие люди/en",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 12 букв/en",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "swashbuckler",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "swashbucklers",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Английский",
  "lang_code": "en",
  "pos": "noun",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "прилагательные"
      ],
      "word": "swashbuckling"
    },
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "swashbuckle"
    }
  ],
  "senses": [
    {
      "glosses": [
        "головорез, сорвиголова"
      ],
      "id": "ru-swashbuckler-en-noun-dF2LvsWl"
    },
    {
      "glosses": [
        "боевик, произведение приключенческого жанра (с головорезом в качестве главного героя или действующего лица)"
      ],
      "id": "ru-swashbuckler-en-noun-I-SMoZkQ"
    },
    {
      "glosses": [
        "хвастун, бахвал"
      ],
      "id": "ru-swashbuckler-en-noun-DB6bFs5U"
    }
  ],
  "sounds": [
    {
      "ipa": "ˈswɔʃˌbʌklə"
    }
  ],
  "word": "swashbuckler"
}
{
  "categories": [
    "Английские существительные",
    "Английский язык",
    "Нет сведений о составе слова",
    "Нужна этимология",
    "Плохие люди/en",
    "Слова из 12 букв/en"
  ],
  "etymology_text": "От ??",
  "forms": [
    {
      "form": "swashbuckler",
      "tags": [
        "singular"
      ]
    },
    {
      "form": "swashbucklers",
      "tags": [
        "plural"
      ]
    }
  ],
  "lang": "Английский",
  "lang_code": "en",
  "pos": "noun",
  "related": [
    {
      "raw_tags": [
        "Ближайшее родство",
        "прилагательные"
      ],
      "word": "swashbuckling"
    },
    {
      "raw_tags": [
        "Ближайшее родство",
        "глаголы"
      ],
      "word": "swashbuckle"
    }
  ],
  "senses": [
    {
      "glosses": [
        "головорез, сорвиголова"
      ]
    },
    {
      "glosses": [
        "боевик, произведение приключенческого жанра (с головорезом в качестве главного героя или действующего лица)"
      ]
    },
    {
      "glosses": [
        "хвастун, бахвал"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˈswɔʃˌbʌklə"
    }
  ],
  "word": "swashbuckler"
}

Download raw JSONL data for swashbuckler meaning in Английский (1.1kB)


This page is a part of the kaikki.org machine-readable Английский dictionary. This dictionary is based on structured data extracted on 2024-11-06 from the ruwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.