See Zola in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "Английские существительные", "parents": [], "source": "w" }, { "kind": "other", "name": "Английский язык", "parents": [], "source": "w" }, { "kind": "other", "name": "Женские имена/en", "parents": [], "source": "w" }, { "kind": "other", "name": "Слова из 4 букв/en", "parents": [], "source": "w" }, { "kind": "other", "name": "Французские фамилии/en", "parents": [], "source": "w" } ], "lang": "Английский", "lang_code": "en", "pos": "noun", "senses": [ { "glosses": [ "Зола (женское имя)" ], "id": "ru-Zola-en-noun-CMpG2xXH" }, { "glosses": [ "Золя (французская фамилия)" ], "id": "ru-Zola-en-noun-GOq0bPwZ" } ], "word": "Zola" }
{ "categories": [ "Английские существительные", "Английский язык", "Женские имена/en", "Слова из 4 букв/en", "Французские фамилии/en" ], "lang": "Английский", "lang_code": "en", "pos": "noun", "senses": [ { "glosses": [ "Зола (женское имя)" ] }, { "glosses": [ "Золя (французская фамилия)" ] } ], "word": "Zola" }
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This page is a part of the kaikki.org machine-readable Английский dictionary. This dictionary is based on structured data extracted on 2024-11-01 from the ruwiktionary dump dated 2024-10-20 using wiktextract (d49d402 and a5af179). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.