"Spaniard" meaning in All languages combined

See Spaniard on Wiktionary

Noun [Engels]

IPA: /ˈspænjəd/ Audio: en-us-Spaniard-noun.ogg
  1. Spanjaard
    Sense id: nl-Spaniard-en-noun-MTO92rJ5 Categories (other): Demoniem_in_het_Engels Topics: demonym
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "Woorden in het Engels",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Woorden in het Engels met IPA-weergave",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Woorden in het Engels met audioweergave",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Woorden in het Engels van lengte 8",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Zelfstandig naamwoord in het Engels",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "Engels",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Zelfstandig naamwoord",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Demoniem_in_het_Engels",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "text": "Gladiator, are you the one they call the Spaniard?",
          "translation": "Gladiator ben jij de ze noemen de Spanjaard?"
        }
      ],
      "glosses": [
        "Spanjaard"
      ],
      "id": "nl-Spaniard-en-noun-MTO92rJ5",
      "topics": [
        "demonym"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈspænjəd/"
    },
    {
      "audio": "en-us-Spaniard-noun.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f3/En-us-Spaniard-noun.ogg/En-us-Spaniard-noun.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/en-us-Spaniard-noun.ogg"
    }
  ],
  "word": "Spaniard"
}
{
  "categories": [
    "Woorden in het Engels",
    "Woorden in het Engels met IPA-weergave",
    "Woorden in het Engels met audioweergave",
    "Woorden in het Engels van lengte 8",
    "Zelfstandig naamwoord in het Engels"
  ],
  "lang": "Engels",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "Zelfstandig naamwoord",
  "senses": [
    {
      "categories": [
        "Demoniem_in_het_Engels"
      ],
      "examples": [
        {
          "text": "Gladiator, are you the one they call the Spaniard?",
          "translation": "Gladiator ben jij de ze noemen de Spanjaard?"
        }
      ],
      "glosses": [
        "Spanjaard"
      ],
      "topics": [
        "demonym"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "/ˈspænjəd/"
    },
    {
      "audio": "en-us-Spaniard-noun.ogg",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f3/En-us-Spaniard-noun.ogg/En-us-Spaniard-noun.ogg.mp3",
      "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/en-us-Spaniard-noun.ogg"
    }
  ],
  "word": "Spaniard"
}

Download raw JSONL data for Spaniard meaning in All languages combined (0.8kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-02-22 from the nlwiktionary dump dated 2025-02-21 using wiktextract (9e2b7d3 and f2e72e5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.