"psychiatrist" meaning in All languages combined

See psychiatrist on Wiktionary

Noun [영어]

  1. 정신과 의사
    Sense id: ko-psychiatrist-en-noun-QGdZjg8F
The following are not (yet) sense-disambiguated
Categories (other): 영어 명사
{
  "categories": [
    {
      "kind": "other",
      "name": "영어 명사",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "영어",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "명사",
  "senses": [
    {
      "examples": [
        {
          "text": "What do intelligence agencies want to meet consult a psychiatrist about? 정보기관이 무엇에 대해서 상의하려고 정신과 의사를 만나기를 원한다는 것인가요?"
        }
      ],
      "glosses": [
        "정신과 의사"
      ],
      "id": "ko-psychiatrist-en-noun-QGdZjg8F"
    }
  ],
  "word": "psychiatrist"
}
{
  "categories": [
    "영어 명사"
  ],
  "lang": "영어",
  "lang_code": "en",
  "pos": "noun",
  "pos_title": "명사",
  "senses": [
    {
      "examples": [
        {
          "text": "What do intelligence agencies want to meet consult a psychiatrist about? 정보기관이 무엇에 대해서 상의하려고 정신과 의사를 만나기를 원한다는 것인가요?"
        }
      ],
      "glosses": [
        "정신과 의사"
      ]
    }
  ],
  "word": "psychiatrist"
}

Download raw JSONL data for psychiatrist meaning in All languages combined (0.4kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-06-04 from the kowiktionary dump dated 2025-06-01 using wiktextract (5ee713e and f1c2b61). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.