See colonel on Wiktionary
{
"categories": [
{
"kind": "other",
"name": "루마니아어 군사",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "루마니아어 외래어",
"parents": [],
"source": "w"
}
],
"etymology_texts": [
"< 중세프랑스어 coronel(< 이탈리아어 colonnello)"
],
"lang": "영어",
"lang_code": "en",
"pos": "unknown",
"senses": [
{
"examples": [
{
"ref": ":w:en:Cuba",
"text": "Both Agramonte and Hevia had decided to name Col. Ramón Barquín to head the Cuban armed forces after the elections. 아그라몬테와 에비아는 라몬 바르킨 대령을 선거가 끝난 뒤 쿠바의 군대를 이끌도록 임명할 것을 결정하였었다."
}
],
"glosses": [
"(미) (육군·공군·해병대) 대령."
],
"id": "ko-colonel-en-unknown-1wQv5U1K",
"note": "약어는Col."
}
],
"sounds": [
{
"audio": "en-us-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f0/En-us-colonel.ogg/En-us-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/en-us-colonel.ogg",
"tags": [
"US"
]
},
{
"ipa": "ˈkɝnəl",
"tags": [
"US"
]
},
{
"ipa": "ˈkɜːnəl",
"tags": [
"UK"
]
},
{
"audio": "en-us-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f0/En-us-colonel.ogg/En-us-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/en-us-colonel.ogg",
"tags": [
"US"
]
},
{
"ipa": "ˈkɝnəl",
"tags": [
"US"
]
},
{
"ipa": "ˈkɜːnəl",
"tags": [
"UK"
]
}
],
"word": "colonel"
}
{
"categories": [
{
"kind": "other",
"name": "미국 영어",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "영어 군사",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "영어 명사",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "영어 외래어",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "프랑스어 군사",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "프랑스어 외래어",
"parents": [],
"source": "w"
}
],
"etymology_texts": [
"< 프랑스어 colonel(< 이탈리아어 colonnello)"
],
"lang": "루마니아어",
"lang_code": "ro",
"pos": "unknown",
"senses": [
{
"glosses": [
"대령."
],
"id": "ko-colonel-ro-unknown-T2bpz915"
}
],
"word": "colonel"
}
{
"etymology_texts": [
"< 이탈리아어 colonnello"
],
"lang": "프랑스어",
"lang_code": "fr",
"pos": "unknown",
"senses": [
{
"glosses": [
"대령."
],
"id": "ko-colonel-fr-unknown-T2bpz915"
}
],
"sounds": [
{
"audio": "Fr-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/b/b9/Fr-colonel.ogg/Fr-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Fr-colonel.ogg"
},
{
"ipa": "kɔ.lɔ.ˈnɛl"
},
{
"audio": "Fr-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/b/b9/Fr-colonel.ogg/Fr-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Fr-colonel.ogg"
},
{
"ipa": "kɔ.lɔ.ˈnɛl"
}
],
"word": "colonel"
}
{
"categories": [
"미국 영어",
"영어 군사",
"영어 명사",
"영어 외래어",
"프랑스어 군사",
"프랑스어 외래어"
],
"etymology_texts": [
"< 프랑스어 colonel(< 이탈리아어 colonnello)"
],
"lang": "루마니아어",
"lang_code": "ro",
"pos": "unknown",
"senses": [
{
"glosses": [
"대령."
]
}
],
"word": "colonel"
}
{
"categories": [
"루마니아어 군사",
"루마니아어 외래어"
],
"etymology_texts": [
"< 중세프랑스어 coronel(< 이탈리아어 colonnello)"
],
"lang": "영어",
"lang_code": "en",
"pos": "unknown",
"senses": [
{
"examples": [
{
"ref": ":w:en:Cuba",
"text": "Both Agramonte and Hevia had decided to name Col. Ramón Barquín to head the Cuban armed forces after the elections. 아그라몬테와 에비아는 라몬 바르킨 대령을 선거가 끝난 뒤 쿠바의 군대를 이끌도록 임명할 것을 결정하였었다."
}
],
"glosses": [
"(미) (육군·공군·해병대) 대령."
],
"note": "약어는Col."
}
],
"sounds": [
{
"audio": "en-us-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f0/En-us-colonel.ogg/En-us-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/en-us-colonel.ogg",
"tags": [
"US"
]
},
{
"ipa": "ˈkɝnəl",
"tags": [
"US"
]
},
{
"ipa": "ˈkɜːnəl",
"tags": [
"UK"
]
},
{
"audio": "en-us-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/f/f0/En-us-colonel.ogg/En-us-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/en-us-colonel.ogg",
"tags": [
"US"
]
},
{
"ipa": "ˈkɝnəl",
"tags": [
"US"
]
},
{
"ipa": "ˈkɜːnəl",
"tags": [
"UK"
]
}
],
"word": "colonel"
}
{
"etymology_texts": [
"< 이탈리아어 colonnello"
],
"lang": "프랑스어",
"lang_code": "fr",
"pos": "unknown",
"senses": [
{
"glosses": [
"대령."
]
}
],
"sounds": [
{
"audio": "Fr-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/b/b9/Fr-colonel.ogg/Fr-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Fr-colonel.ogg"
},
{
"ipa": "kɔ.lɔ.ˈnɛl"
},
{
"audio": "Fr-colonel.ogg",
"mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/b/b9/Fr-colonel.ogg/Fr-colonel.ogg.mp3",
"ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/Fr-colonel.ogg"
},
{
"ipa": "kɔ.lɔ.ˈnɛl"
}
],
"word": "colonel"
}
Download raw JSONL data for colonel meaning in All languages combined (2.3kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-03-01 from the kowiktionary dump dated 2025-02-21 using wiktextract (7c21d10 and f2e72e5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.