"brocht" meaning in All languages combined

See brocht on Wiktionary

Verb [스코트어]

IPA: broxt
  1. bring의 과거형/과거분사.
    Sense id: ko-brocht-unknown-verb-J2pKgQnz
The following are not (yet) sense-disambiguated
Categories (other): 스코트어 동사, 스코트어 동사변화형
{
  "categories": [
    {
      "kind": "other",
      "name": "스코트어 동사",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "스코트어 동사변화형",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "스코트어",
  "lang_code": "unknown",
  "pos": "verb",
  "pos_title": "동사",
  "senses": [
    {
      "glosses": [
        "bring의 과거형/과거분사."
      ],
      "id": "ko-brocht-unknown-verb-J2pKgQnz"
    }
  ],
  "sounds": [
    {
      "ipa": "broxt"
    }
  ],
  "word": "brocht"
}

{
  "categories": [
    "스코트어 동사",
    "스코트어 동사변화형"
  ],
  "lang": "스코트어",
  "lang_code": "unknown",
  "pos": "verb",
  "pos_title": "동사",
  "senses": [
    {
      "glosses": [
        "bring의 과거형/과거분사."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "broxt"
    }
  ],
  "word": "brocht"
}

Download raw JSONL data for brocht meaning in All languages combined (0.3kB)

This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-02-17 from the kowiktionary dump dated 2025-02-02 using wiktextract (ca09fec and c40eb85). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.