"Romeo" meaning in All languages combined

See Romeo on Wiktionary

unknown [영어]

  1. 셰익스피어 연극 '로미오와 줄리엣'의 남자 주인공 이름 로미오.
    Sense id: ko-Romeo-en-unknown-yg2LzMEM
The following are not (yet) sense-disambiguated
Categories (other): 영어 명사, 영어 인명
{
  "categories": [
    {
      "kind": "other",
      "name": "영어 명사",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "영어 인명",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "영어",
  "lang_code": "en",
  "pos": "unknown",
  "senses": [
    {
      "glosses": [
        "셰익스피어 연극 '로미오와 줄리엣'의 남자 주인공 이름 로미오."
      ],
      "id": "ko-Romeo-en-unknown-yg2LzMEM"
    }
  ],
  "word": "Romeo"
}
{
  "categories": [
    "영어 명사",
    "영어 인명"
  ],
  "lang": "영어",
  "lang_code": "en",
  "pos": "unknown",
  "senses": [
    {
      "glosses": [
        "셰익스피어 연극 '로미오와 줄리엣'의 남자 주인공 이름 로미오."
      ]
    }
  ],
  "word": "Romeo"
}

Download raw JSONL data for Romeo meaning in All languages combined (0.2kB)


This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-01-23 from the kowiktionary dump dated 2025-01-20 using wiktextract (0c0c1f1 and 4230888). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.