"作曲家" meaning in 일본어

See 作曲家 in All languages combined, or Wiktionary

Noun

IPA: sakkʲokɯka
  1. 작곡가.
    Sense id: ko-作曲家-ja-noun-uLb6zdTw
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "일본어 명사",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "일본어 한자어",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "중국어 명사",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "일본어",
  "lang_code": "ja",
  "pos": "noun",
  "pos_title": "명사",
  "senses": [
    {
      "glosses": [
        "작곡가."
      ],
      "id": "ko-作曲家-ja-noun-uLb6zdTw"
    }
  ],
  "sounds": [
    {
      "ipa": "sakkʲokɯka"
    }
  ],
  "word": "作曲家"
}
{
  "categories": [
    "일본어 명사",
    "일본어 한자어",
    "중국어 명사"
  ],
  "lang": "일본어",
  "lang_code": "ja",
  "pos": "noun",
  "pos_title": "명사",
  "senses": [
    {
      "glosses": [
        "작곡가."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "sakkʲokɯka"
    }
  ],
  "word": "作曲家"
}

Download raw JSONL data for 作曲家 meaning in 일본어 (0.3kB)


This page is a part of the kaikki.org machine-readable 일본어 dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the kowiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.