"Connacht" meaning in 아일랜드어

{
  "lang": "아일랜드어",
  "lang_code": "ga",
  "pos": "name",
  "pos_title": "고유 명사",
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Inflections with a red link for lemma",
          "parents": [],
          "source": "w"
        },
        {
          "kind": "other",
          "name": "아일랜드어 비표준 문자가 포함된 낱말 (링크)",
          "parents": [],
          "source": "w"
        }
      ],
      "form_of": [
        {
          "word": "Connachta"
        }
      ],
      "glosses": [
        "속격 형태의 Connachta"
      ],
      "id": "ko-Connacht-ga-name-xtWZRcpo",
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "Connacht"
}

{
  "lang": "아일랜드어",
  "lang_code": "ga",
  "pos": "name",
  "pos_title": "고유 명사",
  "senses": [
    {
      "categories": [
        "Inflections with a red link for lemma",
        "아일랜드어 비표준 문자가 포함된 낱말 (링크)"
      ],
      "form_of": [
        {
          "word": "Connachta"
        }
      ],
      "glosses": [
        "속격 형태의 Connachta"
      ],
      "tags": [
        "form-of"
      ]
    }
  ],
  "word": "Connacht"
}

{
  "called_from": "ko/page/63",
  "msg": "unknown title: 변이",
  "path": [
    "Connacht"
  ],
  "section": "아일랜드어",
  "subsection": "",
  "title": "Connacht",
  "trace": ""
}

{
  "called_from": "luaexec/683",
  "msg": "LUA error in #invoke('languages/templates', 'getByCode', 'ga', 'makeEntryName', 'Connachta', '') parent ('틀:inflection of', {1: 'ga', 2: 'Connachta', 3: '', 4: 'gen'})",
  "path": [
    "Connacht",
    "Template:inflection of",
    "Template:no deprecated lang param usage",
    "ARGVAL-1",
    "#ifeq",
    "#ifeq",
    "TEMPLATE_NAME",
    "#invoke",
    "#invoke"
  ],
  "section": "아일랜드어",
  "subsection": "",
  "title": "Connacht",
  "trace": "[string \"Module:parameters\"]:167: Internal error: \"full language\" is not a recognized parameter type."
}