"здрав" meaning in 불가리아어

See здрав in All languages combined, or Wiktionary

Adjective

IPA: zdraf
  1. 건강한.
    Sense id: ko-здрав-bg-adj-ht4gH2xg
The following are not (yet) sense-disambiguated
Categories (other): 불가리아어 형용사
{
  "categories": [
    {
      "kind": "other",
      "name": "불가리아어 형용사",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "< 슬라브조어 *sъdorvъ"
  ],
  "lang": "불가리아어",
  "lang_code": "bg",
  "pos": "adj",
  "pos_title": "형용사",
  "senses": [
    {
      "examples": [
        {
          "text": "로마자 표기: zdrav"
        }
      ],
      "glosses": [
        "건강한."
      ],
      "id": "ko-здрав-bg-adj-ht4gH2xg"
    }
  ],
  "sounds": [
    {
      "ipa": "zdraf"
    }
  ],
  "word": "здрав"
}
{
  "categories": [
    "불가리아어 형용사"
  ],
  "etymology_texts": [
    "< 슬라브조어 *sъdorvъ"
  ],
  "lang": "불가리아어",
  "lang_code": "bg",
  "pos": "adj",
  "pos_title": "형용사",
  "senses": [
    {
      "examples": [
        {
          "text": "로마자 표기: zdrav"
        }
      ],
      "glosses": [
        "건강한."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "zdraf"
    }
  ],
  "word": "здрав"
}

Download raw JSONL data for здрав meaning in 불가리아어 (0.3kB)


This page is a part of the kaikki.org machine-readable 불가리아어 dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the kowiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.