See bastard in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "ルーマニア語", "parents": [], "source": "w" }, { "kind": "other", "name": "ルーマニア語 イタリア語由来", "parents": [], "source": "w" }, { "kind": "other", "name": "ルーマニア語_イタリア語借用語", "parents": [], "source": "w" }, { "kind": "other", "name": "ルーマニア語_名詞", "parents": [], "source": "w" } ], "etymology_texts": [ "イタリア語 bastardo からの借用語" ], "forms": [ { "form": "bastarzi", "tags": [ "plural" ] } ], "lang": "ルーマニア語", "lang_code": "ro", "pos": "noun", "pos_title": "名詞", "senses": [ { "glosses": [ "私生児、庶子。" ], "id": "ja-bastard-ro-noun-yywjOzTH" } ], "word": "bastard" }
{ "categories": [ "ルーマニア語", "ルーマニア語 イタリア語由来", "ルーマニア語_イタリア語借用語", "ルーマニア語_名詞" ], "etymology_texts": [ "イタリア語 bastardo からの借用語" ], "forms": [ { "form": "bastarzi", "tags": [ "plural" ] } ], "lang": "ルーマニア語", "lang_code": "ro", "pos": "noun", "pos_title": "名詞", "senses": [ { "glosses": [ "私生児、庶子。" ] } ], "word": "bastard" }
Download raw JSONL data for bastard meaning in ルーマニア語 (0.4kB)
This page is a part of the kaikki.org machine-readable ルーマニア語 dictionary. This dictionary is based on structured data extracted on 2024-11-28 from the jawiktionary dump dated 2024-11-21 using wiktextract (65a6e81 and 0dbea76). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.