See 調和平均 on Wiktionary
{ "categories": [ { "kind": "other", "name": "日本語", "parents": [], "source": "w" }, { "kind": "other", "name": "日本語_名詞", "parents": [], "source": "w" }, { "kind": "other", "name": "日本語_統計学", "parents": [], "source": "w" } ], "forms": [ { "form": "ちょうわへいきん" } ], "lang": "日本語", "lang_code": "ja", "pos": "noun", "pos_title": "名詞", "senses": [ { "glosses": [ "データの各数値の逆数を取り、それら逆数の算術平均を取り、さらに逆数を取った値。データが n 個存在し、データのそれぞれの値が x₁, x₂, ..., xₙ であるとき、 dfrac 1tfrac 1n( tfrac 1x_1+ tfrac 1x_2,...,+ tfrac 1x_n)=1/(n⁻¹∑ᵢ₌₁ⁿx_i⁻¹)から得られる値。" ], "id": "ja-調和平均-ja-noun-H2dPucp~" } ], "translations": [ { "lang": "英語", "lang_code": "en", "word": "harmonic mean" } ], "word": "調和平均" }
{ "categories": [ "日本語", "日本語_名詞", "日本語_統計学" ], "forms": [ { "form": "ちょうわへいきん" } ], "lang": "日本語", "lang_code": "ja", "pos": "noun", "pos_title": "名詞", "senses": [ { "glosses": [ "データの各数値の逆数を取り、それら逆数の算術平均を取り、さらに逆数を取った値。データが n 個存在し、データのそれぞれの値が x₁, x₂, ..., xₙ であるとき、 dfrac 1tfrac 1n( tfrac 1x_1+ tfrac 1x_2,...,+ tfrac 1x_n)=1/(n⁻¹∑ᵢ₌₁ⁿx_i⁻¹)から得られる値。" ] } ], "translations": [ { "lang": "英語", "lang_code": "en", "word": "harmonic mean" } ], "word": "調和平均" }
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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-02-06 from the jawiktionary dump dated 2025-02-02 using wiktextract (0ee4b87 and 9dbd323). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
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