See peritia in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "ラテン語", "parents": [], "source": "w" }, { "kind": "other", "name": "ラテン語 名詞", "parents": [], "source": "w" } ], "descendants": [ { "lang": "イタリア語", "lang_code": "it", "word": "perizia" }, { "lang": "ポルトガル語", "lang_code": "pt", "word": "perícia" } ], "etymology_texts": [ "peritus 参照。" ], "forms": [ { "form": "perītia", "tags": [ "canonical" ] }, { "form": "perītiae" }, { "form": "属格: perītiae" } ], "lang": "ラテン語", "lang_code": "la", "pos": "noun", "pos_title": "名詞", "senses": [ { "glosses": [ "経験。経験に基づく知識。専門的知識。" ], "id": "ja-peritia-la-noun-KriIBOry", "ruby": [ [ "基", "もと" ] ] } ], "word": "peritia" }
{ "categories": [ "ラテン語", "ラテン語 名詞" ], "descendants": [ { "lang": "イタリア語", "lang_code": "it", "word": "perizia" }, { "lang": "ポルトガル語", "lang_code": "pt", "word": "perícia" } ], "etymology_texts": [ "peritus 参照。" ], "forms": [ { "form": "perītia", "tags": [ "canonical" ] }, { "form": "perītiae" }, { "form": "属格: perītiae" } ], "lang": "ラテン語", "lang_code": "la", "pos": "noun", "pos_title": "名詞", "senses": [ { "glosses": [ "経験。経験に基づく知識。専門的知識。" ], "ruby": [ [ "基", "もと" ] ] } ], "word": "peritia" }
Download raw JSONL data for peritia meaning in ラテン語 (0.6kB)
This page is a part of the kaikki.org machine-readable ラテン語 dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the jawiktionary dump dated 2024-12-20 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.