See Эйзенбергов in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "Formes de noms de famille en russe", "parents": [], "source": "w" }, { "kind": "other", "name": "Russe", "orig": "russe", "parents": [], "source": "w" } ], "lang": "Russe", "lang_code": "ru", "pos": "name", "pos_title": "Forme de nom de famille", "raw_tags": [ "masculin animé" ], "senses": [ { "form_of": [ { "word": "Эйзенберг" } ], "glosses": [ "Génitif pluriel de Эйзенберг." ], "id": "fr-Эйзенбергов-ru-name-7ULgjDc-" }, { "form_of": [ { "word": "Эйзенберг" } ], "glosses": [ "Accusatif pluriel de Эйзенберг." ], "id": "fr-Эйзенбергов-ru-name-XH4jwELU" } ], "tags": [ "form-of", "surename" ], "word": "Эйзенбергов" }
{ "categories": [ "Formes de noms de famille en russe", "russe" ], "lang": "Russe", "lang_code": "ru", "pos": "name", "pos_title": "Forme de nom de famille", "raw_tags": [ "masculin animé" ], "senses": [ { "form_of": [ { "word": "Эйзенберг" } ], "glosses": [ "Génitif pluriel de Эйзенберг." ] }, { "form_of": [ { "word": "Эйзенберг" } ], "glosses": [ "Accusatif pluriel de Эйзенберг." ] } ], "tags": [ "form-of", "surename" ], "word": "Эйзенбергов" }
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This page is a part of the kaikki.org machine-readable Russe dictionary. This dictionary is based on structured data extracted on 2024-08-29 from the frwiktionary dump dated 2024-08-20 using wiktextract (b78692a and f99c758). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
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