See Зборовских in All languages combined, or Wiktionary
{
"categories": [
{
"kind": "other",
"name": "Formes de noms de famille en russe",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Russe",
"orig": "russe",
"parents": [],
"source": "w"
}
],
"lang": "Russe",
"lang_code": "ru",
"pos": "name",
"pos_title": "Forme de nom de famille",
"senses": [
{
"glosses": [
"Accusatif pluriel de Зборовский."
],
"id": "fr-Зборовских-ru-name-ZJzuAdGc"
},
{
"glosses": [
"Génitif pluriel de Зборовский."
],
"id": "fr-Зборовских-ru-name-iv2D1Hej"
},
{
"glosses": [
"Locatif pluriel de Зборовский."
],
"id": "fr-Зборовских-ru-name-RVw~4vIN"
}
],
"tags": [
"form-of",
"surename"
],
"word": "Зборовских"
}
{
"categories": [
"Formes de noms de famille en russe",
"russe"
],
"lang": "Russe",
"lang_code": "ru",
"pos": "name",
"pos_title": "Forme de nom de famille",
"senses": [
{
"glosses": [
"Accusatif pluriel de Зборовский."
]
},
{
"glosses": [
"Génitif pluriel de Зборовский."
]
},
{
"glosses": [
"Locatif pluriel de Зборовский."
]
}
],
"tags": [
"form-of",
"surename"
],
"word": "Зборовских"
}
Download raw JSONL data for Зборовских meaning in Russe (0.4kB)
This page is a part of the kaikki.org machine-readable Russe dictionary. This dictionary is based on structured data extracted on 2025-08-03 from the frwiktionary dump dated 2025-08-01 using wiktextract (a681f8a and 3c020d2). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.