"Годзилла" meaning in Russe

See Годзилла in All languages combined, or Wiktionary

Proper name

IPA: \ɡɐdʲ͡zʲˈzʲiɫə\ Audio: LL-Q7737 (rus)-Tatiana Kerbush-Годзилла.wav
  1. Godzilla.
    Sense id: fr-Годзилла-ru-name-wRZvEGqf Categories (other): Lexique en russe du cinéma Topics: film
The following are not (yet) sense-disambiguated
{
  "categories": [
    {
      "kind": "other",
      "name": "Animaux imaginaires en russe",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Déclinaisons manquantes en russe",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Noms propres en russe",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Russe",
      "orig": "russe",
      "parents": [],
      "source": "w"
    }
  ],
  "lang": "Russe",
  "lang_code": "ru",
  "pos": "name",
  "pos_title": "Nom propre",
  "raw_tags": [
    "Déclinaisons manquantes ou à compléter. (Ajouter)"
  ],
  "senses": [
    {
      "categories": [
        {
          "kind": "other",
          "name": "Lexique en russe du cinéma",
          "parents": [],
          "source": "w"
        }
      ],
      "glosses": [
        "Godzilla."
      ],
      "id": "fr-Годзилла-ru-name-wRZvEGqf",
      "topics": [
        "film"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ɡɐdʲ͡zʲˈzʲiɫə\\"
    },
    {
      "audio": "LL-Q7737 (rus)-Tatiana Kerbush-Годзилла.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/9/99/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/9/99/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav.ogg",
      "raw_tags": [
        "Russie (Saint-Pétersbourg)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q7737 (rus)-Tatiana Kerbush-Годзилла.wav"
    }
  ],
  "word": "Годзилла"
}
{
  "categories": [
    "Animaux imaginaires en russe",
    "Déclinaisons manquantes en russe",
    "Noms propres en russe",
    "russe"
  ],
  "lang": "Russe",
  "lang_code": "ru",
  "pos": "name",
  "pos_title": "Nom propre",
  "raw_tags": [
    "Déclinaisons manquantes ou à compléter. (Ajouter)"
  ],
  "senses": [
    {
      "categories": [
        "Lexique en russe du cinéma"
      ],
      "glosses": [
        "Godzilla."
      ],
      "topics": [
        "film"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ɡɐdʲ͡zʲˈzʲiɫə\\"
    },
    {
      "audio": "LL-Q7737 (rus)-Tatiana Kerbush-Годзилла.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/9/99/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/9/99/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav/LL-Q7737_(rus)-Tatiana_Kerbush-Годзилла.wav.ogg",
      "raw_tags": [
        "Russie (Saint-Pétersbourg)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q7737 (rus)-Tatiana Kerbush-Годзилла.wav"
    }
  ],
  "word": "Годзилла"
}

Download raw JSONL data for Годзилла meaning in Russe (1.0kB)


This page is a part of the kaikki.org machine-readable Russe dictionary. This dictionary is based on structured data extracted on 2024-11-05 from the frwiktionary dump dated 2024-10-20 using wiktextract (fbeafe8 and 7f03c9b). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.