See Айзенбергов in All languages combined, or Wiktionary
Download JSONL data for Айзенбергов meaning in Russe (0.6kB)
{
"categories": [
{
"kind": "other",
"name": "Formes de noms de famille en russe",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Russe",
"orig": "russe",
"parents": [],
"source": "w"
}
],
"lang": "Russe",
"lang_code": "ru",
"pos": "name",
"pos_title": "Forme de nom de famille",
"senses": [
{
"glosses": [
"Accusatif pluriel de Айзенберг."
],
"id": "fr-Айзенбергов-ru-name-suBDjLA4"
},
{
"glosses": [
"Génitif pluriel de Айзенберг."
],
"id": "fr-Айзенбергов-ru-name-k7RRcN0B"
}
],
"tags": [
"form-of",
"surename"
],
"word": "Айзенбергов"
}
{
"categories": [
"Formes de noms de famille en russe",
"russe"
],
"lang": "Russe",
"lang_code": "ru",
"pos": "name",
"pos_title": "Forme de nom de famille",
"senses": [
{
"glosses": [
"Accusatif pluriel de Айзенберг."
]
},
{
"glosses": [
"Génitif pluriel de Айзенберг."
]
}
],
"tags": [
"form-of",
"surename"
],
"word": "Айзенбергов"
}
This page is a part of the kaikki.org machine-readable Russe dictionary. This dictionary is based on structured data extracted on 2024-07-16 from the frwiktionary dump dated 2024-07-01 using wiktextract (446037d and 7cfad79). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.