"funciona" meaning in Portugais

See funciona in All languages combined, or Wiktionary

Verb

IPA: \fũ.sjˈo.nɐ\, \fũ.si.ˈo.nə\, fũ.sjˈo.nɐ, fũ.sjˈo.nɐ Audio: LL-Q5146 (por)-Nelson Ricardo 2500-funciona.wav , LL-Q5146 (por)-Santamarcanda-funciona.wav Forms: você/ele/ela funciona, (2ᵉ personne du singulier) [imperative, present]
  1. Troisième personne du singulier du présent de l’indicatif de funcionar. Form of: funcionar
    Sense id: fr-funciona-pt-verb-H23vsOud
  2. Deuxième personne du singulier de l’impératif de funcionar. Form of: funcionar
    Sense id: fr-funciona-pt-verb-1KoibGXs
The following are not (yet) sense-disambiguated

Download JSONL data for funciona meaning in Portugais (1.9kB)

{
  "categories": [
    {
      "kind": "other",
      "name": "Formes de verbes en portugais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Portugais",
      "orig": "portugais",
      "parents": [],
      "source": "w"
    }
  ],
  "forms": [
    {
      "form": "você/ele/ela funciona"
    },
    {
      "form": "(2ᵉ personne du singulier)",
      "tags": [
        "imperative",
        "present"
      ]
    }
  ],
  "lang": "Portugais",
  "lang_code": "pt",
  "pos": "verb",
  "pos_title": "Forme de verbe",
  "senses": [
    {
      "form_of": [
        {
          "word": "funcionar"
        }
      ],
      "glosses": [
        "Troisième personne du singulier du présent de l’indicatif de funcionar."
      ],
      "id": "fr-funciona-pt-verb-H23vsOud"
    },
    {
      "form_of": [
        {
          "word": "funcionar"
        }
      ],
      "glosses": [
        "Deuxième personne du singulier de l’impératif de funcionar."
      ],
      "id": "fr-funciona-pt-verb-1KoibGXs"
    }
  ],
  "sounds": [
    {
      "ipa": "\\fũ.sjˈo.nɐ\\"
    },
    {
      "ipa": "\\fũ.si.ˈo.nə\\"
    },
    {
      "audio": "LL-Q5146 (por)-Nelson Ricardo 2500-funciona.wav",
      "ipa": "fũ.sjˈo.nɐ",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/15/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/15/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav.ogg",
      "raw_tags": [
        "États-Unis"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q5146 (por)-Nelson Ricardo 2500-funciona.wav"
    },
    {
      "audio": "LL-Q5146 (por)-Santamarcanda-funciona.wav",
      "ipa": "fũ.sjˈo.nɐ",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/6a/LL-Q5146_(por)-Santamarcanda-funciona.wav/LL-Q5146_(por)-Santamarcanda-funciona.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/6a/LL-Q5146_(por)-Santamarcanda-funciona.wav/LL-Q5146_(por)-Santamarcanda-funciona.wav.ogg",
      "raw_tags": [
        "Porto (Portugal)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q5146 (por)-Santamarcanda-funciona.wav"
    }
  ],
  "tags": [
    "form-of"
  ],
  "word": "funciona"
}
{
  "categories": [
    "Formes de verbes en portugais",
    "portugais"
  ],
  "forms": [
    {
      "form": "você/ele/ela funciona"
    },
    {
      "form": "(2ᵉ personne du singulier)",
      "tags": [
        "imperative",
        "present"
      ]
    }
  ],
  "lang": "Portugais",
  "lang_code": "pt",
  "pos": "verb",
  "pos_title": "Forme de verbe",
  "senses": [
    {
      "form_of": [
        {
          "word": "funcionar"
        }
      ],
      "glosses": [
        "Troisième personne du singulier du présent de l’indicatif de funcionar."
      ]
    },
    {
      "form_of": [
        {
          "word": "funcionar"
        }
      ],
      "glosses": [
        "Deuxième personne du singulier de l’impératif de funcionar."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\fũ.sjˈo.nɐ\\"
    },
    {
      "ipa": "\\fũ.si.ˈo.nə\\"
    },
    {
      "audio": "LL-Q5146 (por)-Nelson Ricardo 2500-funciona.wav",
      "ipa": "fũ.sjˈo.nɐ",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/15/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/1/15/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav/LL-Q5146_(por)-Nelson_Ricardo_2500-funciona.wav.ogg",
      "raw_tags": [
        "États-Unis"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q5146 (por)-Nelson Ricardo 2500-funciona.wav"
    },
    {
      "audio": "LL-Q5146 (por)-Santamarcanda-funciona.wav",
      "ipa": "fũ.sjˈo.nɐ",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/6a/LL-Q5146_(por)-Santamarcanda-funciona.wav/LL-Q5146_(por)-Santamarcanda-funciona.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/6/6a/LL-Q5146_(por)-Santamarcanda-funciona.wav/LL-Q5146_(por)-Santamarcanda-funciona.wav.ogg",
      "raw_tags": [
        "Porto (Portugal)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q5146 (por)-Santamarcanda-funciona.wav"
    }
  ],
  "tags": [
    "form-of"
  ],
  "word": "funciona"
}

This page is a part of the kaikki.org machine-readable Portugais dictionary. This dictionary is based on structured data extracted on 2024-07-16 from the frwiktionary dump dated 2024-07-01 using wiktextract (446037d and 7cfad79). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.