See subrogationibus in All languages combined, or Wiktionary
{
"categories": [
{
"kind": "other",
"name": "Formes de noms communs en latin",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "Latin",
"orig": "latin",
"parents": [],
"source": "w"
}
],
"lang": "Latin",
"lang_code": "la",
"pos": "noun",
"pos_title": "Forme de nom commun",
"senses": [
{
"form_of": [
{
"word": "subrogatio"
}
],
"glosses": [
"Datif pluriel de subrogatio."
],
"id": "fr-subrogationibus-la-noun-eaugZImS"
},
{
"form_of": [
{
"word": "subrogatio"
}
],
"glosses": [
"Ablatif pluriel de subrogatio."
],
"id": "fr-subrogationibus-la-noun-ODKbl2uY"
}
],
"tags": [
"form-of"
],
"word": "subrogationibus"
}
{
"categories": [
"Formes de noms communs en latin",
"latin"
],
"lang": "Latin",
"lang_code": "la",
"pos": "noun",
"pos_title": "Forme de nom commun",
"senses": [
{
"form_of": [
{
"word": "subrogatio"
}
],
"glosses": [
"Datif pluriel de subrogatio."
]
},
{
"form_of": [
{
"word": "subrogatio"
}
],
"glosses": [
"Ablatif pluriel de subrogatio."
]
}
],
"tags": [
"form-of"
],
"word": "subrogationibus"
}
Download raw JSONL data for subrogationibus meaning in Latin (0.4kB)
This page is a part of the kaikki.org machine-readable Latin dictionary. This dictionary is based on structured data extracted on 2024-09-08 from the frwiktionary dump dated 2024-09-01 using wiktextract (2f7812a and a107042). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.