"Sherlock Holmes" meaning in Français

See Sherlock Holmes in All languages combined, or Wiktionary

Proper name

IPA: \ʃɛʁ.lɔk hɔlms\
  1. Détective privé inventé par Arthur Conan Doyle en 1854.
    Sense id: fr-Sherlock_Holmes-fr-name-BH2seo09
  2. Personne ayant un grand esprit de déduction. Tags: figuratively
    Sense id: fr-Sherlock_Holmes-fr-name-kwTi2q7Q Categories (other): Métaphores en français
The following are not (yet) sense-disambiguated
Translations: شرلوك هولمز (Šerlwk Hwlms) (Arabe), Շերլոկ Հոլմս (Šerlok Holms) (Arménien), 歇洛克·福尔摩斯 (Xiēluòkè Fúěrmósī) (Chinois), 셜록 홈즈 (Syeollok Homjeu) (Coréen), Ŝerloko Holmso (Espéranto), Σέρλοκ Χολμς (Sérlok Kholms) (Grec), שרלוק הולמס (Šerlwq Hwlms) (Hébreu), シャーロック・ホームズ (Shyārokku Hōmuzu) (Japonais), Шерлок Холмс (Šérlok Hólms) (Macédonien), Шерлок Холмс (Cherlok Kholms) (Russe)

Download JSONL data for Sherlock Holmes meaning in Français (3.1kB)

{
  "categories": [
    {
      "kind": "other",
      "name": "Noms propres en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Noms propres en français",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en arabe",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en arménien",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en chinois",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en coréen",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en espéranto",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en grec",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en hébreu",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en japonais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en macédonien",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Traductions en russe",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Français",
      "orig": "français",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_texts": [
    "De l’anglais."
  ],
  "lang": "Français",
  "lang_code": "fr",
  "pos": "name",
  "pos_id": "fr-nom-pr-1",
  "pos_title": "Nom propre",
  "senses": [
    {
      "examples": [
        {
          "ref": "Les Nouvelles Aventures de Lucky Luke, 2001, épisode 3",
          "text": "« Nous, on a Kiku Luke. Il est meilleur que votre Sherlock Holmes.\n— Meilleur que Sherlock Holmes ? It’s impossible. »"
        }
      ],
      "glosses": [
        "Détective privé inventé par Arthur Conan Doyle en 1854."
      ],
      "id": "fr-Sherlock_Holmes-fr-name-BH2seo09"
    },
    {
      "categories": [
        {
          "kind": "other",
          "name": "Métaphores en français",
          "parents": [],
          "source": "w"
        }
      ],
      "examples": [
        {
          "ref": "Serge Berland-Delépine, La grammaire anglaise de l'étudiant, 1989",
          "text": "La lecture fréquente des romans policiers lui fait croire qu’il est un Sherlock Holmes."
        }
      ],
      "glosses": [
        "Personne ayant un grand esprit de déduction."
      ],
      "id": "fr-Sherlock_Holmes-fr-name-kwTi2q7Q",
      "tags": [
        "figuratively"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ʃɛʁ.lɔk hɔlms\\"
    }
  ],
  "tags": [
    "masculine"
  ],
  "translations": [
    {
      "lang": "Arabe",
      "lang_code": "ar",
      "roman": "Šerlwk Hwlms",
      "word": "شرلوك هولمز"
    },
    {
      "lang": "Arménien",
      "lang_code": "hy",
      "roman": "Šerlok Holms",
      "word": "Շերլոկ Հոլմս"
    },
    {
      "lang": "Chinois",
      "lang_code": "zh",
      "roman": "Xiēluòkè Fúěrmósī",
      "traditional_writing": "夏洛克·福尔摩斯",
      "word": "歇洛克·福尔摩斯"
    },
    {
      "lang": "Coréen",
      "lang_code": "ko",
      "roman": "Syeollok Homjeu",
      "word": "셜록 홈즈"
    },
    {
      "lang": "Espéranto",
      "lang_code": "eo",
      "word": "Ŝerloko Holmso"
    },
    {
      "lang": "Grec",
      "lang_code": "el",
      "roman": "Sérlok Kholms",
      "word": "Σέρλοκ Χολμς"
    },
    {
      "lang": "Hébreu",
      "lang_code": "he",
      "roman": "Šerlwq Hwlms",
      "word": "שרלוק הולמס"
    },
    {
      "lang": "Japonais",
      "lang_code": "ja",
      "roman": "Shyārokku Hōmuzu",
      "word": "シャーロック・ホームズ"
    },
    {
      "lang": "Macédonien",
      "lang_code": "mk",
      "roman": "Šérlok Hólms",
      "word": "Шерлок Холмс"
    },
    {
      "lang": "Russe",
      "lang_code": "ru",
      "roman": "Cherlok Kholms",
      "word": "Шерлок Холмс"
    }
  ],
  "word": "Sherlock Holmes"
}
{
  "categories": [
    "Noms propres en anglais",
    "Noms propres en français",
    "Traductions en arabe",
    "Traductions en arménien",
    "Traductions en chinois",
    "Traductions en coréen",
    "Traductions en espéranto",
    "Traductions en grec",
    "Traductions en hébreu",
    "Traductions en japonais",
    "Traductions en macédonien",
    "Traductions en russe",
    "français"
  ],
  "etymology_texts": [
    "De l’anglais."
  ],
  "lang": "Français",
  "lang_code": "fr",
  "pos": "name",
  "pos_id": "fr-nom-pr-1",
  "pos_title": "Nom propre",
  "senses": [
    {
      "examples": [
        {
          "ref": "Les Nouvelles Aventures de Lucky Luke, 2001, épisode 3",
          "text": "« Nous, on a Kiku Luke. Il est meilleur que votre Sherlock Holmes.\n— Meilleur que Sherlock Holmes ? It’s impossible. »"
        }
      ],
      "glosses": [
        "Détective privé inventé par Arthur Conan Doyle en 1854."
      ]
    },
    {
      "categories": [
        "Métaphores en français"
      ],
      "examples": [
        {
          "ref": "Serge Berland-Delépine, La grammaire anglaise de l'étudiant, 1989",
          "text": "La lecture fréquente des romans policiers lui fait croire qu’il est un Sherlock Holmes."
        }
      ],
      "glosses": [
        "Personne ayant un grand esprit de déduction."
      ],
      "tags": [
        "figuratively"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ʃɛʁ.lɔk hɔlms\\"
    }
  ],
  "tags": [
    "masculine"
  ],
  "translations": [
    {
      "lang": "Arabe",
      "lang_code": "ar",
      "roman": "Šerlwk Hwlms",
      "word": "شرلوك هولمز"
    },
    {
      "lang": "Arménien",
      "lang_code": "hy",
      "roman": "Šerlok Holms",
      "word": "Շերլոկ Հոլմս"
    },
    {
      "lang": "Chinois",
      "lang_code": "zh",
      "roman": "Xiēluòkè Fúěrmósī",
      "traditional_writing": "夏洛克·福尔摩斯",
      "word": "歇洛克·福尔摩斯"
    },
    {
      "lang": "Coréen",
      "lang_code": "ko",
      "roman": "Syeollok Homjeu",
      "word": "셜록 홈즈"
    },
    {
      "lang": "Espéranto",
      "lang_code": "eo",
      "word": "Ŝerloko Holmso"
    },
    {
      "lang": "Grec",
      "lang_code": "el",
      "roman": "Sérlok Kholms",
      "word": "Σέρλοκ Χολμς"
    },
    {
      "lang": "Hébreu",
      "lang_code": "he",
      "roman": "Šerlwq Hwlms",
      "word": "שרלוק הולמס"
    },
    {
      "lang": "Japonais",
      "lang_code": "ja",
      "roman": "Shyārokku Hōmuzu",
      "word": "シャーロック・ホームズ"
    },
    {
      "lang": "Macédonien",
      "lang_code": "mk",
      "roman": "Šérlok Hólms",
      "word": "Шерлок Холмс"
    },
    {
      "lang": "Russe",
      "lang_code": "ru",
      "roman": "Cherlok Kholms",
      "word": "Шерлок Холмс"
    }
  ],
  "word": "Sherlock Holmes"
}

This page is a part of the kaikki.org machine-readable Français dictionary. This dictionary is based on structured data extracted on 2024-06-28 from the frwiktionary dump dated 2024-06-20 using wiktextract (d4b8e84 and b863ecc). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.