See Sherlock Holmes in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "Mots en français issus d’un mot en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Noms propres en français", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en arabe", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en arménien", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en chinois", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en coréen", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en espéranto", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en grec", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en hébreu", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en japonais", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en macédonien", "parents": [], "source": "w" }, { "kind": "other", "name": "Traductions en russe", "parents": [], "source": "w" }, { "kind": "other", "name": "Français", "orig": "français", "parents": [], "source": "w" } ], "etymology_texts": [ "De l’anglais." ], "lang": "Français", "lang_code": "fr", "pos": "name", "pos_title": "Nom propre", "senses": [ { "categories": [ { "kind": "other", "name": "Exemples en français", "parents": [], "source": "w" } ], "examples": [ { "ref": "Les Nouvelles Aventures de Lucky Luke, 2001, épisode 3", "text": "« Nous, on a Kiku Luke. Il est meilleur que votre Sherlock Holmes.\n— Meilleur que Sherlock Holmes ? It’s impossible. »" } ], "glosses": [ "Détective privé inventé par Arthur Conan Doyle en 1854." ], "id": "fr-Sherlock_Holmes-fr-name-BH2seo09" }, { "categories": [ { "kind": "other", "name": "Exemples en français", "parents": [], "source": "w" }, { "kind": "other", "name": "Métaphores en français", "parents": [], "source": "w" } ], "examples": [ { "ref": "Serge Berland-Delépine, La grammaire anglaise de l'étudiant, 1989", "text": "La lecture fréquente des romans policiers lui fait croire qu’il est un Sherlock Holmes." } ], "glosses": [ "Personne ayant un grand esprit de déduction." ], "id": "fr-Sherlock_Holmes-fr-name-kwTi2q7Q", "tags": [ "figuratively" ] } ], "sounds": [ { "ipa": "\\ʃɛʁ.lɔk hɔlms\\" } ], "tags": [ "masculine" ], "translations": [ { "lang": "Arabe", "lang_code": "ar", "roman": "Šerlwk Hwlms", "word": "شرلوك هولمز" }, { "lang": "Arménien", "lang_code": "hy", "roman": "Šerlok Holms", "word": "Շերլոկ Հոլմս" }, { "lang": "Chinois", "lang_code": "zh", "roman": "Xiēluòkè Fúěrmósī", "traditional_writing": "夏洛克·福尔摩斯", "word": "歇洛克·福尔摩斯" }, { "lang": "Coréen", "lang_code": "ko", "roman": "Syeollok Homjeu", "word": "셜록 홈즈" }, { "lang": "Espéranto", "lang_code": "eo", "word": "Ŝerloko Holmso" }, { "lang": "Grec", "lang_code": "el", "roman": "Sérlok Kholms", "word": "Σέρλοκ Χολμς" }, { "lang": "Hébreu", "lang_code": "he", "roman": "Šerlwq Hwlms", "word": "שרלוק הולמס" }, { "lang": "Japonais", "lang_code": "ja", "roman": "Shyārokku Hōmuzu", "word": "シャーロック・ホームズ" }, { "lang": "Macédonien", "lang_code": "mk", "roman": "Šérlok Hólms", "word": "Шерлок Холмс" }, { "lang": "Russe", "lang_code": "ru", "roman": "Cherlok Kholms", "word": "Шерлок Холмс" } ], "word": "Sherlock Holmes" }
{ "categories": [ "Mots en français issus d’un mot en anglais", "Noms propres en français", "Traductions en arabe", "Traductions en arménien", "Traductions en chinois", "Traductions en coréen", "Traductions en espéranto", "Traductions en grec", "Traductions en hébreu", "Traductions en japonais", "Traductions en macédonien", "Traductions en russe", "français" ], "etymology_texts": [ "De l’anglais." ], "lang": "Français", "lang_code": "fr", "pos": "name", "pos_title": "Nom propre", "senses": [ { "categories": [ "Exemples en français" ], "examples": [ { "ref": "Les Nouvelles Aventures de Lucky Luke, 2001, épisode 3", "text": "« Nous, on a Kiku Luke. Il est meilleur que votre Sherlock Holmes.\n— Meilleur que Sherlock Holmes ? It’s impossible. »" } ], "glosses": [ "Détective privé inventé par Arthur Conan Doyle en 1854." ] }, { "categories": [ "Exemples en français", "Métaphores en français" ], "examples": [ { "ref": "Serge Berland-Delépine, La grammaire anglaise de l'étudiant, 1989", "text": "La lecture fréquente des romans policiers lui fait croire qu’il est un Sherlock Holmes." } ], "glosses": [ "Personne ayant un grand esprit de déduction." ], "tags": [ "figuratively" ] } ], "sounds": [ { "ipa": "\\ʃɛʁ.lɔk hɔlms\\" } ], "tags": [ "masculine" ], "translations": [ { "lang": "Arabe", "lang_code": "ar", "roman": "Šerlwk Hwlms", "word": "شرلوك هولمز" }, { "lang": "Arménien", "lang_code": "hy", "roman": "Šerlok Holms", "word": "Շերլոկ Հոլմս" }, { "lang": "Chinois", "lang_code": "zh", "roman": "Xiēluòkè Fúěrmósī", "traditional_writing": "夏洛克·福尔摩斯", "word": "歇洛克·福尔摩斯" }, { "lang": "Coréen", "lang_code": "ko", "roman": "Syeollok Homjeu", "word": "셜록 홈즈" }, { "lang": "Espéranto", "lang_code": "eo", "word": "Ŝerloko Holmso" }, { "lang": "Grec", "lang_code": "el", "roman": "Sérlok Kholms", "word": "Σέρλοκ Χολμς" }, { "lang": "Hébreu", "lang_code": "he", "roman": "Šerlwq Hwlms", "word": "שרלוק הולמס" }, { "lang": "Japonais", "lang_code": "ja", "roman": "Shyārokku Hōmuzu", "word": "シャーロック・ホームズ" }, { "lang": "Macédonien", "lang_code": "mk", "roman": "Šérlok Hólms", "word": "Шерлок Холмс" }, { "lang": "Russe", "lang_code": "ru", "roman": "Cherlok Kholms", "word": "Шерлок Холмс" } ], "word": "Sherlock Holmes" }
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This page is a part of the kaikki.org machine-readable Français dictionary. This dictionary is based on structured data extracted on 2025-01-10 from the frwiktionary dump dated 2025-01-01 using wiktextract (df33d17 and 4ed51a5). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.