See zed in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "Lemmes en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Mots en anglais issus d’un mot en grec ancien", "parents": [], "source": "w" }, { "kind": "other", "name": "Mots en anglais issus d’un mot en hébreu ancien", "parents": [], "source": "w" }, { "kind": "other", "name": "Mots en anglais issus d’un mot en latin", "parents": [], "source": "w" }, { "kind": "other", "name": "Mots en anglais issus d’un mot en moyen français", "parents": [], "source": "w" }, { "kind": "other", "name": "Noms communs en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Anglais", "orig": "anglais", "parents": [], "source": "w" } ], "etymology_texts": [ "(début XVᵉ siècle) Du moyen français zede, du latin zēta, du grec ancien ζῆτα, zễta (« zêta »), de l’hébreu ancien zayin (nom de la lettre, littéralement « poignard »)." ], "forms": [ { "form": "zeds", "ipas": [ "\\zɛdz\\" ], "tags": [ "plural" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "noun", "pos_title": "Nom commun", "senses": [ { "categories": [ { "kind": "other", "name": "Anglais du Commonwealth", "orig": "anglais du Commonwealth", "parents": [], "source": "w" } ], "glosses": [ "Z, z (lettre de l’alphabet latin)." ], "id": "fr-zed-en-noun-bF-xMGkU", "raw_tags": [ "Commonwealth" ] } ], "sounds": [ { "ipa": "\\zɛd\\" }, { "audio": "En-au-zed.ogg", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/dd/En-au-zed.ogg/En-au-zed.ogg.mp3", "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-au-zed.ogg", "raw_tags": [ "Australie" ] } ], "synonyms": [ { "word": "izzard" }, { "word": "ezod" }, { "word": "uzzard" }, { "raw_tags": [ "États-Unis" ], "word": "zee" }, { "word": "zod" } ], "tags": [ "masculine" ], "word": "zed" }
{ "categories": [ "Lemmes en anglais", "Mots en anglais issus d’un mot en grec ancien", "Mots en anglais issus d’un mot en hébreu ancien", "Mots en anglais issus d’un mot en latin", "Mots en anglais issus d’un mot en moyen français", "Noms communs en anglais", "anglais" ], "etymology_texts": [ "(début XVᵉ siècle) Du moyen français zede, du latin zēta, du grec ancien ζῆτα, zễta (« zêta »), de l’hébreu ancien zayin (nom de la lettre, littéralement « poignard »)." ], "forms": [ { "form": "zeds", "ipas": [ "\\zɛdz\\" ], "tags": [ "plural" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "noun", "pos_title": "Nom commun", "senses": [ { "categories": [ "anglais du Commonwealth" ], "glosses": [ "Z, z (lettre de l’alphabet latin)." ], "raw_tags": [ "Commonwealth" ] } ], "sounds": [ { "ipa": "\\zɛd\\" }, { "audio": "En-au-zed.ogg", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/dd/En-au-zed.ogg/En-au-zed.ogg.mp3", "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-au-zed.ogg", "raw_tags": [ "Australie" ] } ], "synonyms": [ { "word": "izzard" }, { "word": "ezod" }, { "word": "uzzard" }, { "raw_tags": [ "États-Unis" ], "word": "zee" }, { "word": "zod" } ], "tags": [ "masculine" ], "word": "zed" }
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This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2024-11-03 from the frwiktionary dump dated 2024-10-20 using wiktextract (d6bf104 and a5af179). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.