See glob in All languages combined, or Wiktionary
{ "categories": [ { "kind": "other", "name": "Lemmes en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Mots en anglais issus d’un mot en latin", "parents": [], "source": "w" }, { "kind": "other", "name": "Noms communs en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Anglais", "orig": "anglais", "parents": [], "source": "w" } ], "etymology_texts": [ "De globule, du latin globulus." ], "forms": [ { "form": "globs", "ipas": [ "\\ɡlɑbz\\" ], "tags": [ "plural" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "noun", "pos_title": "Nom commun", "senses": [ { "glosses": [ "Globule (corps microscopique sphérique ou sphéroïdal)." ], "id": "fr-glob-en-noun-7Gv~NmTj" }, { "categories": [ { "kind": "other", "name": "Lexique en anglais de la programmation", "parents": [], "source": "w" } ], "glosses": [ "Ensemble de métacaractères moins complexe que les expressions rationnelles." ], "id": "fr-glob-en-noun-eB64prt8", "topics": [ "programming" ] } ], "sounds": [ { "ipa": "\\ɡlɑb\\" }, { "audio": "En-us-glob.ogg", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d5/En-us-glob.ogg/En-us-glob.ogg.mp3", "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-glob.ogg", "raw_tags": [ "États-Unis" ] }, { "ipa": "\\ɡlɑb\\", "raw_tags": [ "(États-Unis)" ] }, { "ipa": "\\ɡlɒb\\", "raw_tags": [ "(Royaume-Uni)" ] }, { "audio": "LL-Q1860 (eng)-Wodencafe-glob.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.ogg", "raw_tags": [ "Texas (États-Unis)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Wodencafe-glob.wav" } ], "word": "glob" } { "categories": [ { "kind": "other", "name": "Lemmes en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Mots en anglais issus d’un mot en latin", "parents": [], "source": "w" }, { "kind": "other", "name": "Verbes en anglais", "parents": [], "source": "w" }, { "kind": "other", "name": "Anglais", "orig": "anglais", "parents": [], "source": "w" } ], "etymology_texts": [ "De globule, du latin globulus." ], "forms": [ { "form": "to glob", "ipas": [ "\\ɡlɑb\\" ], "tags": [ "infinitive" ] }, { "form": "globs", "ipas": [ "\\ɡlɑbz\\" ], "tags": [ "present", "third-person", "singular" ] }, { "form": "globbed", "ipas": [ "\\ɡlɑbd\\" ], "tags": [ "preterite" ] }, { "form": "globbed", "ipas": [ "\\ɡlɑbd\\" ], "tags": [ "participle", "past" ] }, { "form": "globbing", "ipas": [ "\\ɡlɑb.ɪŋ\\" ], "tags": [ "participle", "present" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "verb", "pos_title": "Verbe", "senses": [ { "categories": [ { "kind": "other", "name": "Lexique en anglais de la programmation", "parents": [], "source": "w" } ], "glosses": [ "Utiliser du glob." ], "id": "fr-glob-en-verb-FExblNNF", "topics": [ "programming" ] } ], "sounds": [ { "ipa": "\\ɡlɑb\\" }, { "audio": "En-us-glob.ogg", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d5/En-us-glob.ogg/En-us-glob.ogg.mp3", "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-glob.ogg", "raw_tags": [ "États-Unis" ] }, { "ipa": "\\ɡlɑb\\", "raw_tags": [ "(États-Unis)" ] }, { "ipa": "\\ɡlɒb\\", "raw_tags": [ "(Royaume-Uni)" ] }, { "audio": "LL-Q1860 (eng)-Wodencafe-glob.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.ogg", "raw_tags": [ "Texas (États-Unis)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Wodencafe-glob.wav" } ], "word": "glob" }
{ "categories": [ "Lemmes en anglais", "Mots en anglais issus d’un mot en latin", "Noms communs en anglais", "anglais" ], "etymology_texts": [ "De globule, du latin globulus." ], "forms": [ { "form": "globs", "ipas": [ "\\ɡlɑbz\\" ], "tags": [ "plural" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "noun", "pos_title": "Nom commun", "senses": [ { "glosses": [ "Globule (corps microscopique sphérique ou sphéroïdal)." ] }, { "categories": [ "Lexique en anglais de la programmation" ], "glosses": [ "Ensemble de métacaractères moins complexe que les expressions rationnelles." ], "topics": [ "programming" ] } ], "sounds": [ { "ipa": "\\ɡlɑb\\" }, { "audio": "En-us-glob.ogg", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d5/En-us-glob.ogg/En-us-glob.ogg.mp3", "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-glob.ogg", "raw_tags": [ "États-Unis" ] }, { "ipa": "\\ɡlɑb\\", "raw_tags": [ "(États-Unis)" ] }, { "ipa": "\\ɡlɒb\\", "raw_tags": [ "(Royaume-Uni)" ] }, { "audio": "LL-Q1860 (eng)-Wodencafe-glob.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.ogg", "raw_tags": [ "Texas (États-Unis)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Wodencafe-glob.wav" } ], "word": "glob" } { "categories": [ "Lemmes en anglais", "Mots en anglais issus d’un mot en latin", "Verbes en anglais", "anglais" ], "etymology_texts": [ "De globule, du latin globulus." ], "forms": [ { "form": "to glob", "ipas": [ "\\ɡlɑb\\" ], "tags": [ "infinitive" ] }, { "form": "globs", "ipas": [ "\\ɡlɑbz\\" ], "tags": [ "present", "third-person", "singular" ] }, { "form": "globbed", "ipas": [ "\\ɡlɑbd\\" ], "tags": [ "preterite" ] }, { "form": "globbed", "ipas": [ "\\ɡlɑbd\\" ], "tags": [ "participle", "past" ] }, { "form": "globbing", "ipas": [ "\\ɡlɑb.ɪŋ\\" ], "tags": [ "participle", "present" ] } ], "lang": "Anglais", "lang_code": "en", "pos": "verb", "pos_title": "Verbe", "senses": [ { "categories": [ "Lexique en anglais de la programmation" ], "glosses": [ "Utiliser du glob." ], "topics": [ "programming" ] } ], "sounds": [ { "ipa": "\\ɡlɑb\\" }, { "audio": "En-us-glob.ogg", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/d/d5/En-us-glob.ogg/En-us-glob.ogg.mp3", "ogg_url": "https://commons.wikimedia.org/wiki/Special:FilePath/En-us-glob.ogg", "raw_tags": [ "États-Unis" ] }, { "ipa": "\\ɡlɑb\\", "raw_tags": [ "(États-Unis)" ] }, { "ipa": "\\ɡlɒb\\", "raw_tags": [ "(Royaume-Uni)" ] }, { "audio": "LL-Q1860 (eng)-Wodencafe-glob.wav", "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.mp3", "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/4/45/LL-Q1860_(eng)-Wodencafe-glob.wav/LL-Q1860_(eng)-Wodencafe-glob.wav.ogg", "raw_tags": [ "Texas (États-Unis)" ], "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Wodencafe-glob.wav" } ], "word": "glob" }
Download raw JSONL data for glob meaning in Anglais (3.1kB)
This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2025-04-17 from the frwiktionary dump dated 2025-04-03 using wiktextract (ada610d and ea19a0a). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.