all-out in Anglais

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "Adjectifs en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Lemmes en anglais",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Anglais",
      "orig": "anglais",
      "parents": [],
      "source": "w"
    }
  ],
  "derived": [
    {
      "translation": "n'y en avoir plus",
      "word": "be all out"
    },
    {
      "translation": "y aller à fond",
      "word": "go all out"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "adj",
  "pos_title": "Adjectif",
  "senses": [
    {
      "glosses": [
        "Général, qui concerne tout le monde."
      ],
      "id": "fr-all-out-en-adj-5E7Evaoo"
    },
    {
      "glosses": [
        "Maximum, d'ampleur inégalée."
      ],
      "id": "fr-all-out-en-adj-W~sodD~Y"
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˌɔːlˈaʊt\\"
    },
    {
      "audio": "LL-Q1860 (eng)-Flame, not lame-all-out.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/c0/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/c0/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav.ogg",
      "raw_tags": [
        "Milwaukee (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Flame, not lame-all-out.wav"
    }
  ],
  "synonyms": [
    {
      "word": "global"
    }
  ],
  "word": "all-out"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "Adjectifs en anglais",
    "Lemmes en anglais",
    "anglais"
  ],
  "derived": [
    {
      "translation": "n'y en avoir plus",
      "word": "be all out"
    },
    {
      "translation": "y aller à fond",
      "word": "go all out"
    }
  ],
  "lang": "Anglais",
  "lang_code": "en",
  "pos": "adj",
  "pos_title": "Adjectif",
  "senses": [
    {
      "glosses": [
        "Général, qui concerne tout le monde."
      ]
    },
    {
      "glosses": [
        "Maximum, d'ampleur inégalée."
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "\\ˌɔːlˈaʊt\\"
    },
    {
      "audio": "LL-Q1860 (eng)-Flame, not lame-all-out.wav",
      "mp3_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/c0/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav.mp3",
      "ogg_url": "https://upload.wikimedia.org/wikipedia/commons/transcoded/c/c0/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav/LL-Q1860_(eng)-Flame,_not_lame-all-out.wav.ogg",
      "raw_tags": [
        "Milwaukee (États-Unis)"
      ],
      "wav_url": "https://commons.wikimedia.org/wiki/Special:FilePath/LL-Q1860 (eng)-Flame, not lame-all-out.wav"
    }
  ],
  "synonyms": [
    {
      "word": "global"
    }
  ],
  "word": "all-out"
}

This page is a part of the kaikki.org machine-readable Anglais dictionary. This dictionary is based on structured data extracted on 2025-04-23 from the frwiktionary dump dated 2025-04-20 using wiktextract (813e02a and ea19a0a). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"all-out" meaning in Anglais

Adjective